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Dmitry_Shevchenko [17]
3 years ago
10

A 5.00 g sample of water vapor, initially at 155°C is cooled at atmospheric pressure, producing ice at –55°C. Calculate the amou

nt of heat energy lost by the water sample in this process, in kJ. Use the following data: specific heat capacity of ice is 2.09 J/g×K; specific heat capacity of liquid water is 4.18 J/g×K; specific heat capacity of water vapor is 1.84 J/g×K; heat of fusion of ice is 336 J/g; heat of vaporization of water is 2260 J/g.
Physics
1 answer:
romanna [79]3 years ago
3 0

Answer:

total energy lost = 16.1 KJ

Explanation:

Heat of vapor to water  =  1.84j/gK is - because have a loss of energy

Heat lost during cooling from 155 to 100 = 1.84x 5 x(155 + 273 - 100+273) = 506J

latent heat of steam = 2260J/g x 5g = 11300J

Heat lost during cooling from 100 to 0 = 4.18 x5 x (100 - 0) = 2090J

Heat due to fusion is = 336J/g x 5g = 1680J

heat to cool ice of 0 to -55 =  2.09J/gK x 5g x (0 -(-55)) = 574.75J

the sum of all H = H of reaction

506J + 11300J + 2090J + 1680J + 574.75J = 16150.75J = 16.1KJ

total energy lost = 16.1 KJ

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Answer:

that would be analyzing data I believe

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3 years ago
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MacGyver is riding on a skateboard and moving west of the velocity of 7 m/s. Macgyver has a mass of 92 kg and the skateboard has
ivann1987 [24]

Answer:

64.5

Explanation:

(m1 + m2) v initial = (m1 * v1 final) + (m2 * v2 final)

(92 + 8)(-7) = (92 x 2) + (8 x v2 final)

(100)(-7) = (184) + (8 x v2 final)

-700 = (184) +  (8 x v2 final)

-516 =  (8 x v2 final)

-516/8 = v2 final

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8 0
3 years ago
A sphere of radius 0.03m has a point charge of q= 7.6 micro C located at it’s centre. Find the electric flux through it?
GalinKa [24]

Answer:

The electric flux through the sphere is 8.58 *10^{5} \frac{Nm^2}{C}

Explanation:

Given

Radius,\ r = 0.03m\\Charge,\ q =7.6\µC

Required

Find the electric flux

Electric flux is calculated using the following formula;

Ф = q/ε

Where ε is the electric constant permitivitty

ε = 8.8542 * 10^{-12}

Substitute ε = 8.8542 * 10^{-12} and q =7.6\µC; The formula becomes

Ф = \frac{7.6\µC}{8.8542 * 10^{-12}}

Ф = \frac{7.6 * 10^{-6}}{8.8542 * 10^{-12}}

Ф = \frac{7.6}{8.8542} *\frac{10^{-6}}{10^{-12}}

Ф = \frac{7.6}{8.8542} *10^{12-6}}

Ф = 0.85834970974 *10^{12-6}}

Ф = 0.85834970974 *10^{6}}

Ф = 8.5834970974 *10^{5}}

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Hence, the electric flux through the sphere is 8.58 *10^{5} \frac{Nm^2}{C}

7 0
3 years ago
1) Beth rode the Flying Saucer ride at her favorite amusement park. The ride hung from a rod and swung back and forth while simu
quester [9]

#1

Since Beth rode the Flying saucer ride which is spinning on its axis while axis is moving to and fro as well, so here Beth will experience two motions in this case

(i) Spinning motion

(ii) Rotational motion

#2

Jill and Scott both traveled for 30 min

So time of motion for both is 0.5 h as we know that 1 h = 60 min

Now from the formula of speed we know that

speed = \frac{distance}{time}

Speed of Jill

v_1 = \frac{5}{0.5} = 10 km/h

speed of Scott

v_2 = \frac{10}{0.5} = 20 km/h

so correct answer is

B) Scott had the faster speed since he rode at 20 k/h while Jill only traveled 10 km/h.

#3

Since we know that <em>acceleration is rate of change in velocity</em>

So here we can say that every motion where velocity changes with time then it is an accelerated motion.

Now change in velocity occurs when either the magnitude will change or its direction will change because here velocity is a vector quantity and it will change with magnitude and direction both.

so here due to oval path the direction of velocity will changes at many points and hence it will be an accelerated motion.

so correct answer is

<em>C) James was right since the car changed direction during the race.</em>


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Inertia is the tendency of an object to resist a change in its motion.
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