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3 years ago

Why do solid have fixed shape?

2 answers:

7 0

Any matter that is a solid has a definiteshape and a definite volume. The molecules in a solid are in fixedpositions and are close together. Although the molecules can still vibrate, they cannot move from one part of the solid to another part. As a result, a solid does not easily change its shape or its volume.

Alja [10]3 years ago

4 0

B. Would be your answer

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A ruler of length 0.30m is pivoted at its centre. Equal and opposite forces of magnitude 2.0N are applied to the ends of the rul

kow [346]

Answer:

0.3858 Nm

Explanation:

The torque of the couple is the dot product of the force vector and the couple vector from 1 end of the ruler to the center. This equals to the product of their magnitude times the cosine() of the angle made by their direction:

$T = \vec{F} \cdot \vec{s} = Fscos(50^0) = 2 * 0.3 * 0.643 = 0.3858 Nm$

6 0

3 years ago

For the rotational part of the experiment, a student measures a force of 1.8 n when the radius is 12 cm and the angular velocity

Dmitry [639]

<span>Ans : The total measured force will be : total centripetal force F = m*r*w^2 F = force r = radius w = angular velocity 1.8 = m*0.12*10^2 mass m = 0.15 kg</span>

6 0

3 years ago

In a hydroelectric power plant, water flows from an elevation of 400 ft to a turbine, where electric power is generated. For an

VashaNatasha [74]

Answer:

$V=3.475ft^3/s=3.48ft^3/s$

Explanation:

We have here values from SI and English Units. I will convert the units to English Units.

We hace for the power P,

$P= 100kW \rightarrow 100kW*(\frac{737.56ft.lbf/s}{1kW})$

$P= 73.7*10^{3}ft.lbf/s$

we have other values such $h=400ft$ and $\gamma= 62.42lb/ft^3$ (specific weight of the water), and 0.85 for \eta

We need to figure the flow rate of the water (V) out, that is,

$V=\frac{P}{\gamma h \eta_0}$

Where $\eta_0$ is the turbine efficiency, at which is,

$\eta_0 = \frac{P}{\gamma Vh}$

Replacing,

$V=\frac{73.7*10^{3}}{62.42*400*0.85}$

$V=3.475ft^3/s$

With this value (the target of this question) we can also calculate the mass flow rate of the waters,

through the density and the flow rate,

$m=\rho V\\m= 3.475*1.94 \\m=6.7415 slugs/s$

converting the slugs to lbm, 1slug = 32.174lbm, we have that the mass flow rate of the water is,

$m= 217lbm/s$

6 0

3 years ago

A 50 gram meterstick is placed on a fulcrum at its 50 cm mark. A 20 gram mass is attached at the 12 cm mark. Where should a 40 g

alekssr [168]

Answer:

The 40g mass will be attached at 69 cm

Explanation:

First, make a sketch of the meterstick with the masses placed on it;

--------------------------------------------------------------------------

↓ Δ ↓

20 g.................50 cm.................40g

38 cm y cm

Apply principle of moment;

sum of clockwise moment = sum of anticlockwise moment

40y = 20 (38)

40y = 760

y = 760 / 40

y = 19 cm

Therefore, the 40g mass will be attached at 50cm + 19cm = 69 cm

12cm 50 cm 69cm

--------------------------------------------------------------------------

↓ Δ ↓

20 g.................50 cm.................40g

38 cm 19 cm

5 0

3 years ago

Both the electrical force and the gravitational force between two objects share which relationship?

julia-pushkina [17]

Answer:

B. They are inversely proportional to the square of the distance.

Explanation:

The gravitational force between two objects is given by:

$F_G = G \frac{m_1 m_2}{r^2}$

where

G is the gravitational constant

m1, m2 are the masses of the two objects

r is the distance between the two objects

While the electrical force is given by

$F_E = k \frac{q_1 q_2}{r^2}$

where

k is the Coulomb's constant

q1, q2 are the charges of the two objects

r is the distance between the two objects

As we see from the two equations, both forces are inversely proportional to the square of the distance, so the correct option is

B. They are inversely proportional to the square of the distance.

7 0

4 years ago