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Studentka2010 [4]
3 years ago
13

1) Beth rode the Flying Saucer ride at her favorite amusement park. The ride hung from a rod and swung back and forth while simu

ltaneously spinning in a circle. What type of motion did Beth experience?
A) Translational motion
B) Spinning motion
C) Rotational motion
D) Translational and rotational motion


2) Jill and Scott both road their bikes for 30 minutes. Jill traveled 5 kilometers and Scott traveled 10. Calculate each person's speed and tell who rode faster. (s=d/t)

A) Scott had the faster speed since he rode at 10 km/h and Jill was riding at 5 km/h
B) Scott had the faster speed since he rode at 20 k/h while Jill only traveled 10 km/h.
C) Jill was traveling faster. She was riding at a speed of 10 km/h while Scott was traveling at 20 km/h.
D) Both Jill and Scott were traveling at the same speed since they both rode their bikes for 30 minutes.

3) James and Haley went to the speedway to watch cars race around an oval track. One car traveled at a constant speed for the entire race. James told Haley that the car was accelerating during race, but Haley said James was wrong since the car traveled at a constant speed. Who was right and why?

A) Haley was right since the car didn't win the race it was not accelerating.
B) Haley was right because the car traveled at a constant speed. Acceleration is a change in velocity.
C) James was right since the car changed direction during the race.
D) James was right because the car was a race car and all race cars accelerate during a race.
Physics
2 answers:
quester [9]3 years ago
6 0

#1

Since Beth rode the Flying saucer ride which is spinning on its axis while axis is moving to and fro as well, so here Beth will experience two motions in this case

(i) Spinning motion

(ii) Rotational motion

#2

Jill and Scott both traveled for 30 min

So time of motion for both is 0.5 h as we know that 1 h = 60 min

Now from the formula of speed we know that

speed = \frac{distance}{time}

Speed of Jill

v_1 = \frac{5}{0.5} = 10 km/h

speed of Scott

v_2 = \frac{10}{0.5} = 20 km/h

so correct answer is

B) Scott had the faster speed since he rode at 20 k/h while Jill only traveled 10 km/h.

#3

Since we know that <em>acceleration is rate of change in velocity</em>

So here we can say that every motion where velocity changes with time then it is an accelerated motion.

Now change in velocity occurs when either the magnitude will change or its direction will change because here velocity is a vector quantity and it will change with magnitude and direction both.

so here due to oval path the direction of velocity will changes at many points and hence it will be an accelerated motion.

so correct answer is

<em>C) James was right since the car changed direction during the race.</em>


BaLLatris [955]3 years ago
3 0

Answer:

1. Option D) Translational and rotational motion.

2. Option B) Scott had the faster speed since he rode at 20 k/h while Jill only traveled 10 km/h.

3. Option C) James was right since the car changed direction during the race.

Explanation:

1. Thinking process:

The object in question is a flying saucer. So there is an element of rotational motion. Next, the saucer is swung. This means that there are two motions - rotational and translational.

2. Jill = 10 km/h

    Sott = 20 km/h

Hence Scott was faster

3. An object is accelerating when three things take place:

  • the velocity of the object is changing.
  • the direction of the object is changing, e.g. car on a circular race course
  • both the direction and acceleration are changing.

Thus, according to the definition above, James is correct.

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If the magnitude of the electric field in air exceeds roughly 3 ✕ 106 N/C, the air breaks down and a spark forms. For a two-disk
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Answer:

1.843 x 10^-5 C  

Explanation:

<u><em>Givens:   </em></u>

It is given that the air starts ionizing when the electric field in the air exceeds a magnitude of 3 x 10^6 N/C, which means that the max electric field can stand without forming a spark is 3 x 10^6 N/C.  

Also it is given that the radius of the disk is 50 cm, it is required to find out the max amount of charge that the disk can hold without forming spark, which means the charge that would produce the max magnitude of the electric field that air can stand without forming spark, and since we know that the electric field in between 2 disk "Capacitor" is given by the following equation  

E = (Q/A)/∈o                                (1)

Where,

Q: total charge on the disk.

A: the area of the disk.  

<u><em>Calculations:  </em></u>

We want to find the quantity of charge on the disk that would produce an electric field of 3 x 10^6 N/C, knowing the radius of the disk we can find the cross-section of the disk, thus substituting in equation (1) we find the maximum quantity of charge the disk can hold  

Q = EA∈o

   = (3 x 10^6) x (π*0.50) x (8.85 x 10^-12)  

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note:

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Explanation:

Only few supernova are observed in our galaxy -

Type II supernovae ( i.e. the explosions of the massive stars ) occurred in the Milky Way, and they might be hidden by the intervening dust if they are located in the more distant parts of our Galaxy .

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3 0
3 years ago
a. What proportion of resistors have resistances less than 90 Ω? b. Find the mean resistance. c. Find the standard deviation of
Anettt [7]

Answer:

a) 0.0625 = 6.25%

b) 106.67 Ω

c) 9.43 Ω

d) 1

Explanation:

The probability distribution is given as

f(x) = (x - 80)/800 for 80 < x < 120

f(x) = 0 otherwise.

f(x) = (x/800) - (0.1)

a) Proportion of resistors with resistance less than 90 Ω

P(X < 90) = ∫⁹⁰₈₀ f(x) dx

∫⁹⁰₈₀ f(x) dx = ∫⁹⁰₈₀ [(x/800) - (0.1)]

= [(x²/1600) - 0.1x]⁹⁰₈₀

= [(90²/1600) - 0.1(90)] - [(80²/1600) - 0.1(80)]

= (5.0625 - 9) - [4 - 8]

= -3.9375 + 4 = 0.0625 = 6.25%

b) The mean is given by the expected value expression E(X) = = Σ xᵢpᵢ (with the sum done all over the data set for each variable and its corresponding probability)

It can be written in integral form as

Mean = ∫¹²⁰₈₀ xf(x) dx (with the integral done all over the probability function, i.e. from, 80 to 120)

Mean = ∫¹²⁰₈₀ x[(x/800) - (0.1)] dx

= ∫¹²⁰₈₀ [(x²/800) - (0.1x)] dx

= [(x³/2400) - (0.05x²)]¹²⁰₈₀

= [(120³/2400) - (0.05(120²)] - [(80³/2400) - (0.05(80²)]

= [720 - 720] - [213.33 - 320] = 106.67 Ω

c) Standard deviation = √(variance)

Variance = Var(X) = Σx²p − μ²

μ = mean = expected value = 106.67 Ω

Σx²p = ∫¹²⁰₈₀ x²f(x) dx = ∫¹²⁰₈₀ x² [(x/800) - (0.1)] dx = ∫¹²⁰₈₀ [(x³/800) - (0.1x²)] dx

= [(x⁴/3200) - (0.0333x³)]¹²⁰₈₀

= [(120⁴/3200) - (0.0333(120³)] - [(80⁴/3200) - (0.0333(80)³)]

= (64800 - 57600) - (12800 - 17066.667)

= 11466.667

Variance = 11466.667 - 106.67² = 88.85

Standard deviation = √88.85 = 9.43 Ω

d) Cdf = sum of probabilities over the entire probability function

Cdf = ∫¹²⁰₈₀ f(x) dx = ∫¹²⁰₈₀ [(x/800) - (0.1)] dx

= [(x²/1600) - 0.1x]¹²⁰₈₀ = [(120²/1600) - 0.1(120)] - [(80²/1600) - 0.1(80)] = (9 - 12) - (4 - 8) = -3+4 = 1 as it should be!!!

Hope this Helps!!!

4 0
3 years ago
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