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masya89 [10]
3 years ago
6

Which estimation could be used to make sure the answer is reasonable? Claudia mixed 16.7 pounds of sand with 12.6 pounds of soil

. She used 22.1 pounds of this mixture to fill a garden pot. How much of the mixture was left over? A. Answer: The amount left over was 7.2 pounds. Estimation: 16.7 + 12.6 is about 30. 30 pounds – 22 pounds = 8 pounds The amount left over was a little less than 8 pounds. B. Answer: The amount left over was 51.4 pounds. Estimation: 16.7 + 12.6 is about 30. 30 pounds + 22 pounds = 52 pounds The amount left over was about 52 pounds. C. Answer: The amount left over was 5.9 pounds. Estimation: 16 + 12 is about 28. 28 pounds – 22 pounds = 6 pounds The amount left over was a little less than 6 pounds.
I NEED HELP FAST 1ST PERSON GETS BRAINLIEST AND TEN PTS
Mathematics
1 answer:
ra1l [238]3 years ago
7 0
The answer for your question is a). Because if you add 12.6 pounds by 16.7 pounds you will get 29.3 as your answer.the estimated answer is 30 and,22.1 estimated is 22.Finally,you just subtract 30 by 22 and you get your answer as 8.
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How do you calculate median
Anna35 [415]
Put all numbers in smallest to largest order
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6 0
3 years ago
What are the roots of this equation? x2-4x+9=0
zysi [14]

Considering the definition of zeros of a function, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

<h3>Zeros of a function</h3>

The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.

In summary, the roots or zeros of the quadratic function are those values ​​of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.

In a quadratic function that has the form:

f(x)= ax² + bx + c

the zeros or roots are calculated by:

x1,x2=\frac{-b+-\sqrt{b^{2}-4ac } }{2a}

<h3>This case</h3>

The quadratic function is f(x) = x² + 4x +9

Being:

  • a= 1
  • b= 4
  • c= 9

the zeros or roots are calculated as:

x1=\frac{-4+\sqrt{4^{2}-4x1x9 } }{2x1}

x1=\frac{-4+\sqrt{16-36 } }{2x1}

x1=\frac{-4+\sqrt{-20 } }{2x1}

and

x2=\frac{-4-\sqrt{4^{2}-4x1x9 } }{2x1}

x2=\frac{-4-\sqrt{16-36 } }{2x1}

x2=\frac{-4-\sqrt{-20} }{2x1}

If the content of the root is negative, the root will have no solution within the set of real numbers. Then \sqrt{-20} has no solution.

Finally, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

Learn more about the zeros of a quadratic function:

brainly.com/question/842305

brainly.com/question/14477557

#SPJ1

6 0
1 year ago
Factor completely 6n^2-18n
lubasha [3.4K]
6n^2-18n

1.find your GCF
 "6n"

final answer;
6n(n-3)
8 0
3 years ago
$36,000,000 is what percent of $90,000,000?
jeka57 [31]
$36,000,000 is 40% of $90,000,000. Hope it helps!
6 0
3 years ago
Read 2 more answers
The cheetah is 7/6 the Perigen falcon is 10/3
Brilliant_brown [7]
The answer is 2  \frac{1}{6}.

Explanation:

In order to subtract the fractions, we must make them like fractions. To do this, the denominators must be the same by multiplying (only). Since the first fraction is \frac{10}{3}, 3 can be multiplied by 2 to get 6, which is the other fraction, we can multiply it. Whatever you do to the denominator you must do to the numerator. Now multiply 2 by the numerator (10) to get \frac{20}{6}. Now we can subtract the fractions \frac{20}{6} and \frac{7}{6} to get 13/6. Since this fraction is not in mixed fraction form yet, we must do that first.  goes into 13 twice, so the whole number is 2 and there is still 1 left, making the fraction \frac{1}{6}. Therefore, the difference is 2 \frac{1}{6}.
8 0
3 years ago
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