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ddd [48]
3 years ago
13

Find two numbers with a sum of 20 and a difference of 14.

Mathematics
1 answer:
vivado [14]3 years ago
4 0
A and B Definitely. 3 and 17, -3 and -17
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Given the function f(x) = x² + 3x - 2 What is the average rate of change for the function from 2 to 6? Show your work.
11Alexandr11 [23.1K]

The average rate of change is 11

Explanation:

The given function is f(x)=x^{2}+3 x-2

We need to determine the average rate of change for the function from 2 to 6

The average rate of change can be determined using the formula,

\frac{f(b)-f(a)}{b-a}

where a=2 and b=6

Now, we shall determine the values of f(2) and f(6) by substituting the values for x = 2 and x = 6 in the function f(x)=x^{2}+3 x-2

Thus, we have,

f(2)=2^{2}+3 (2)-2

       =4+6-2

f(2)=8

Similarly, substituting x = 6, we get,

f(6)=6^{2}+3 (6)-2

       =36+18-2

f(6)=52

Hence, substituting these values in the formula \frac{f(b)-f(a)}{b-a} , we get,

\frac{f(b)-f(a)}{b-a}=\frac{52-8}{6-2}

Simplifying, we get,

\frac{f(b)-f(a)}{b-a}=\frac{44}{4}=11

Thus, the average rate of change for the function from 2 to 6 is 11

7 0
3 years ago
Simplify (2x^2+3)(x+4
Leya [2.2K]

Answer:

23+32−5+12 is the equaequation simplified

Step-by-step explanation:

4 0
3 years ago
What is the 5th term in the sequence d(n)=5/16 (2)^n−1
Verizon [17]

Answer:

Therefore the 5th term is 5.

Step-by-step explanation:

Given:

Sequence is

d(n)=\dfrac{5}{16}2^{n-1}

To Find:

5th term, d(5) = ?

Solution:

d(n)=\dfrac{5}{16}2^{n-1} ....Given

For 5th term put n = 5 then we get

d(5)=\dfrac{5}{16}2^{5-1}=\dfrac{5}{16}\times 2^{4}\\\\d(5)=\dfrac{5}{16}\times 16=5\\\\\therefore d(5)=5

Therefore the 5th term is 5.

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3 years ago
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Answer:

113

Step-by-step explanation:

4 0
3 years ago
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The first figure is dilated to form the second figure.
Rom4ik [11]

the answer is 4. just divide the two numbers and wala you have the answer please mark brainlest

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