Fatih parasının ilk %30unu sonra %35ini harcar ve geriye 105 TL’si kalır. Fatih’in toplamda kaç TL’si vardır?

Mathematics

1 answer:

Vilka [71]2 years ago

8 0

Answer:

is good by his guan yes is help to me

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(8b^2/3*9t^3/5)(8b^5/3*9t^3/5)

erma4kov [3.2K]

Answer:

5,184•b•t^6/5

Step-by-step explanation:

Here, we want to multiply the expressions

According to indices law, if we have same bases, we add up the exponents

Thus, we have that;

8 *8b^(2/3+5/3) * 9 * 9 * t^(3/5+3/5)

= 64 * b * 81 * t^6/5

= 5,184bt^6/5

8 0

3 years ago

Pls help me on this pofavor

Elanso [62]

You are right: the graph does not represent a proportion, because it does not go thru the origin.

3 0

3 years ago

The comprehensive strength of concrete is normally distributed with μ = 2500 psi and σ = 50 psi. Find the probability that a ran

VARVARA [1.3K]

Answer:

The probability that the diameter falls in the interval from 2499 psi to 2510 psi is 0.00798.

Step-by-step explanation:

Let's define the random variable, $X =$ "Comprehensive strength of concrete". We have information that $X$ is normally distributed with a mean of 2500 psi and a standard deviation of 50 psi (or a variance of 2500 psi). In other words, $X \sim N(2500, 2500)$ .

We want to know the probability of the mean of X or $\bar{X}$ that falls in the interval $[2499;2510]$ . From inference theory we know that :

$\bar{X} \sim N(2500, \frac{2500}{5}) \Rightarrow \bar{X} \sim N(2500,500)$

Now we can find the probability as follows:

$P(2499 \leq \bar{X} \leq 2510) \Rightarrow P(\frac{2499 - 2500}{500} \leq \frac{\bar{X} - 2500}{500} \leq \frac{2499 - 2500}{500} ) \Rightarrow\\\Rightarrow P(-0.002 \leq \frac{\bar{X} - 2500}{500} \leq 0.02 ) \Rightarrow P(-0.002 \leq Z \leq 0.02 )$