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artcher [175]
3 years ago
13

Is the prime factorization below correct? 24 24+2.3.4 O Correct Incorrect

Mathematics
1 answer:
xenn [34]3 years ago
5 0
Is the prime factorization below correct

24
24+2.3.4



Answer: 100


Prime numbers are natural numbers (positive whole numbers that sometimes include 0 in certain definitions) that are greater than 1, that cannot be formed by multiplying two smaller numbers. An example of a prime number is 7, since it can only be formed by multiplying the numbers 1 and 7. Other examples include 2, 3, 5, 11, etc.
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Eloise has 3/4 -pound of bird seeds. Each day, she feeds the birds in her yard 1/8 -pound of seeds. For how many days will she b
bulgar [2K]

Answer:

6 days

Step-by-step explanation:

First, we make common denominators:

3 *2  =  6

_  ->     _

4 *2  =  8

and we get 6/8

6/8 divided by 1/8 will be 6 days

3 0
2 years ago
Please help me with 3 and 4 and I think this problem is talking abt problem 2 I posted for help
Naddika [18.5K]
1/6 for the first question and 1/3 for the second
8 0
3 years ago
I need help solving polynomial in standard form​
tangare [24]

Step-by-step explanation:

standard form of

1 . = x⁴-2x ²+3

2. = 5m³- 3m²+ 9m -7

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7 0
2 years ago
There are 2504 computer science students at a school. Of these, 1876 have taken a course in Java, 999 have taken a course in Lin
Y_Kistochka [10]

Answer:

492

Step-by-step explanation:

As per the given data of the question:

Total number of students = 2504

Number of students in Java (J) = 1876

Number of students in Linux (L) = 999

Number of students in C = 345

J∩L = 876

L∩C = 231

C∩J = 290

L∩J∩C = 189

Now according to Venn-diagram as drawn below:

Number of students haven taken courses in Java and Linux both only

= J∩L - L∩J∩C

= 876 - 189

= 687

Number of students haven taken courses in Java and C both only

= C∩J - L∩J∩C

= 290 - 189

= 101

Number of students haven taken courses in C and Linux both only

= L∩C - L∩J∩C

= 231 - 189

= 42

Therefore,

Number of students only in Java = 1876 - 687 - 189 - 101 = 899

Number of students only in Linux = 999 - 687 - 189 - 42 = 81

Number of students only in C = 345 - 42 - 189 - 101 = 13

So,

Number of students who have not taken a course in any of these three subjects

= 2504 - 899 - 81 - 13 - 687 - 189 -101 - 42

= 492

Hence, the students who have not taken a course in any of these three subjects = 492.

6 0
3 years ago
_ABC is a right triangle where m_B = 90Á. The coordinates of A and B are (5, 0) and (2, 5), respectively. If the x-coordinate of
Leokris [45]
Since the triangle is a right triangle at point B, then line AB is perpendicular to line BC.
For perpendicular lines, the product of their slopes is -1.
Slope of AB = (5 - 0)/(2 - 5) = 5/-3 = -5/3
Slope of BC = (y - 5)/(7 - 2) = (y - 5)/5

-5/3(y - 5)/5 = -1
-5(y - 5)/15 = -1
-5(y - 5) = -15
y - 5 = 3
y = 3 + 5 = 8

Therefore, the y-coordinate of point C is 8.
4 0
3 years ago
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