Answer:
Amount invested at 8 % rate = x = $ 15000
Amount invested at 9 % rate = 34000 - x = 34000 - 15000 = $ 19000
Step-by-step explanation:
Total Amount = $ 34000
Let amount invested at 8 % rate = x
Amount invested at 9 % rate = $ 34000 - x
Total interest = $ 2910

291000 = 8 x + 306000 - 9 x
x = 306000 - 291000
x = 15000
So amount invested at 8 % rate = x = $ 15000
Amount invested at 9 % rate = 34000 - x = 34000 - 15000 = $ 19000
I believe this is the right way to write the function
N = [log A − log P] / log(1.0175)
N =[ log (1210.26) - log (1000)]/log (1.0175)
N =log [1210.26/1000] / log (1.0175) = log (1.21026)/log(1.0175) = 0.08288/0.00753 = 11
N = 11 months
Answer:
28 hours
Step-by-step explanation:
let the time period at which the temperature be equal in both Brownsville and Mesquite Texas be 'x'.
Given,
In Brownsville Texas, the temperature is expected to drop 1.5° each hour and In Mesquite Texas, the temperature is expected to drop 2° each hour.
Now, according to the question,
after 'x' hours,
⇒ 80° - 1.5°(x) = 94° - 2°(x)
⇒ 0.5°(x) = 14°
⇒ x = 28
Hence, Till 28 more hours the temperature in Mesquite Texas be greater than that in Brownsville.
Answer:
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