Volume of a cylinder = π r² h
Let us assume the following values:
radius = 9
height = 10
Volume = 3.14 * 9² * 10
= 3.14 * 81 *10
Volume = 2,543.40
Changes:
radius is reduced to 2/9 of its original size = 9 x 2/9 = 2
height is quadrupled = 10 x 4 = 40
Volume = π r² h
= 3.14 * 2² * 40
= 3.14 * 4 * 40
Volume = 502.40
Original volume = 2543.40 V.S. Volume after change = 502.40
The volume of an oblique cylinder decreased when its radius was decreased to 2/9 of its original size and its height is increased 4 times.
I would say 504 basing it off of converting 2/3 into 4/6 and used sets of 84 to each be 1/6
Answer:
20.625 dollars or about 20.63 dollars
Step-by-step explanation:
33/8 = 4.125
4.125 times 5 = 20.625
Answer:x=-5 and x=3
Step-by-step explanation:
log(x^2-15)=log(2x)
Cancel log at both sides we get
x^2-15=2x
Collect like terms
x^2-2x-15=0
x^2-3x+5x-15=0
x(x-3)+5(x-3)=0
(x+5)(x-3)=0
x+5=0 x-3=0
x=-5 x=3
