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NISA [10]
3 years ago
12

Quincy was stuck inside during an afternoon rainstorm. He spent 20 minutes reading, 18 minutes eating lunch, 12 minutes playing

cards, and 10 minutes drawing. For every 10 minutes Quincy was inside he spent 3 minutes ________.
Mathematics
2 answers:
siniylev [52]3 years ago
8 0

Answer: For every 10 minutes Quincy was inside he spent 3 minutes on <u>Lunch.</u>

Step-by-step explanation:

Since we have given that

Number of minutes Quincy spent in reading = 20

Number of minutes he spent in eating lunch = 18

Number of minutes he spent in playing cards = 12

Number of minutes he spent in drawing = 10

Total minutes he spent is given by

20+18+12+10\\\\=60\ minutes

Ratio of lunch to the total minutes is given by

18:60\\\\3:10

So, For every 10 minutes Quincy was inside he spent 3 minutes on<u> Lunch.</u>

Svet_ta [14]3 years ago
7 0
, adding the times of all the activities tells us when she was stuck inside for 1 hour there are 6 ten-minute periods in an hour. 3mins each * 6 of these periods give 18 minutes, the amount of time he was eating lunch
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Charlie's weight is nine kilograms greater than his brother's. Together they weigh 99 kilograms. Let x represent the weight of t
spayn [35]
C=x+9, c+x=99, c=99-x

So we have two equations equal to c, c=x+9 and c=99-x, since c=c:

x+9=99-x

2x+9=99

2x=90

x=45, and since c=x+9, c=54

So Charlie weighs 54 kg and his brother weighs 45 kg.
4 0
3 years ago
A watering can contained 512 quarts water. After all the plants were watered, only 4 cups remained. How many cups of water were
Sedaia [141]

Answer:

2044 cups

Step-by-step explanation:

number of cups left = number of cups in the watering can - number of cups remaining

convert the capacity of the watering can to cups

1 quart = 4 cups

512 x 4 = 2048

2048 - 4 = 2044

8 0
3 years ago
Convert the units.<br> ____ mL = 2L
almond37 [142]

Answer:

2000mL=2L

Step-by-step explanation:

8 0
2 years ago
How can I solve (b)?
dsp73
90/3 parts of silver = 30 times multiplied by
tin = 12 × 30 = 360g
lead = 8 × 30 = 240g

12.5 / 23 = 0.5434 parts per metal

tin = 12 × 0.5434 = 6.5kg
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5 0
3 years ago
Integrate this two questions ​
tankabanditka [31]

Simplify the integrands by polynomial division.

\dfrac{t^2}{1 - 3t} = -\dfrac19 \left(3t + 1 - \dfrac1{1 - 3t}\right)

\dfrac t{1 + 4t} = \dfrac14 \left(1 - \dfrac1{1 + 4t}\right)

Now computing the integrals is trivial.

5.

\displaystyle \int \frac{t^2}{1 - 3t} \, dt = -\frac19 \int \left(3t + 1 - \frac1{1-3t}\right) \, dt \\\\ = -\frac19 \left(\frac32 t^2 + t + \frac13 \ln|1 - 3t|\right) + C \\\\ = \boxed{-\frac{t^2}6 - \frac t9 - \frac{\ln|1-3t|}{27} + C}

where we use the power rule,

\displaystyle \int x^n \, dx = \frac{x^{n+1}}{n+1} + C ~~~~ (n\neq-1)

and a substitution to integrate the last term,

\displaystyle \int \frac{dt}{1-3t} = -\frac13 \int \frac{du}u \\\\ = -\frac13 \ln|u| + C \\\\ = -\frac13 \ln|1-3t| + C ~~~ (u=1-3t \text{ and } du = -3\,dt)

8.

\displaystyle \int \frac t{1+4t} \, dt = \frac14 \int \left(1 - \frac1{1+4t}\right) \, dt \\\\ = \frac14 \left(t - \frac14 \ln|1 + 4t|\right) + C \\\\ = \boxed{\frac t4 - \frac{\ln|1+4t|}{16} + C}

using the same approach as above.

5 0
1 year ago
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