Multiply the the numbers for each locket and see which number is greater
I believe it’s AB AND DF, ZBAC = ZDEF
Answer:
5.131 × 10¹⁴ Hz
Step-by-step explanation:
<u>Planck relation</u>

where:
- E = Energy of the photon (J).
- h = Planck's constant (J · s).
- f = frequency of light produced (Hz).
Given values:
- E = 3.4 × 10⁻¹⁹ J
- h = 6.626 × 10⁻³⁴ J · s
Substitute the given values into the formula and solve for f:






Can you be more specific pls
Answer:
At the beginning of 6th month , Jeff will have in his account $ 520 .
Step-by-step explanation:
At the beginning of 6th month , Jeff will have in his account,
$ 
= $ 
= $ 
= $ 
= $ 520
since, the $ 100 deposited at the end of 1st month earns interest for 4 months till the end of the 5th month, the $ 100 deposited at the end of the 2nd month earns interest for 3 months and so on till the last $100 deposited earns interest for '0' month.