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Margarita [4]
3 years ago
5

The lengths of the diagonals of a rhombus are 18 cm and 24 cm. What is its perimeter and what is the distance between the parall

el sides?
I don't know the distance but the perimeter is 60cm

Mathematics
2 answers:
Virty [35]3 years ago
6 0

Answer:

Perimeter = 60 cm

Distance between the parallel sides = 14.4 cm

Step-by-step explanation:

In the given rhombus ABCD,  AC = 24 cm and BD = 18 cm

As we know in a rhombus BC² = OB² + OC²

BC² = (18/2)²+ (24/2)² = 9² + 12² = 81 + 144 = 225

BC = √225 = 15 cm.

So perimeter of the rhombus = 4×15 = 60 cm

Area of rhombus = (1/2)×Multiplication of diagonals = (1/2)×18×24 = 216 cm²

And from the given diagram area of rhombus ABCD = 2×area of ΔABD

= 2×(1/2)×BC×BE = BC×BE = 15×BE

Since area of rhombus is 216 cm², therefore

15×BE = 216

BE = 216/15 = 14.40 cm

Therefore the distance between two parallel lines is 14.40 cm.

SpyIntel [72]3 years ago
5 0
Try this option:
note, that distance between the parallel sides is shown via formula of area.
If it is possible, check the arithmetic.

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Points E, F, and D are on circle C, and angle G measures 60°. The measure of arc EF equals the measure of arc FD.
galben [10]

Answer:

∠EFD ≅ ∠EGD ⇒ A

Arc ED ≅ arc FD ⇒ C

m arc FD = 120° ⇒ E

Step-by-step explanation:

Let us revise some facts

  1. Equal chords subtended equal arcs
  2. The measure of an inscribed angle is one-half the measure of the central angle which subtended by the same arc
  3. The measure of a central angle is equal to the measure of its subtended arc
  4. If one angle of an isosceles triangle measure 60° then the triangle is equilateral
  5. The sum of the measures of the interior angles of any quadrilateral is 360°

In the quadrilateral  CDGE

∵ m∠G = 60°

∵ m∠GDC = m∠GEC = 90°

- By using the 5th rule above

∴ m∠G + m∠GDC + m∠DCE + m∠GEC = 360°

∴ 60 + 90 + m∠DCE + 90 = 360

∴ 240 + m∠DCE = 360

- Subtract 240 from both sides

∵ m∠DCE = 120°

In circle C

∵ ∠DCE is a central angle subtended by arc DE

∵ ∠DFE is an inscribed angle subtended by arc DE

- By using the 2nd rule above

∴ m∠DFE = \frac{1}{2} m∠∠DCE

∵ m∠DCE = 120°

∴ m∠DFE = \frac{1}{2} (120)

∴ m∠DFE = 60°

- That means ∠EFD ≅ ∠EGD because their measure is 60°

∴ ∠EFD ≅ ∠EGD

In Δ EFD

∵ EF = FD

∵ m∠DFE = 60°

- By using the 4th rule above

∴ Δ EFD is an equilateral triangle

∴ ED = FD = FE

In circle C

∵ Side ED subtended by arc ED

∵ Side FD subtended by FD

∵ Side ED ≅ side FD ⇒ proved

- By using the 1st rule above

∴ Arc ED ≅ arc FD

∵ m∠ECD = 120°

∵ ∠ECD is a central angle subtended by arc ED

- By using the 3rd rule above

∴ m∠ECD = m arc ED

∴ m of arc ED = 120°

∵ Arc ED ≅ arc FD

∴ m arc ED = m arc FD

∴ m arc FD = 120°

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3 years ago
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Juli2301 [7.4K]

Answer:

1/4(1 - 3x)

Step-by-step explanation:

Step 1: Write out expression

1/4 - 3/4x

Step 2: Factor out GCF

1/4(1 - 3x)

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Without actual division prove that x4 +2x3 -2x2 +2x -3 is exactly divisible by<br> x2 +2x-3
Brut [27]

Answer:

Step-by-step explanation:                

\displaystyle\Large\boldsymbol{} x^4+2x^3-2x^2+2x-3= \\\\\\x^4+2x^2(x-1)+2x-\underbrace{2-1}_{-3}=  \\\\\\x^4-1+2x^2(x-1)+2x-2 = \\\\\\(x^2-1)(x^2+1)+2x^2(x-1)+2(x-1) = \\\\\\\underline{(x-1)}(x+1)(x^2+1)+2x^2\underline{(x-1)} +2\underline{(x-1)} =\\\\\\(x-1)((x+1)(x^2+1)+2x^2+2)=\\\\\\(x-1)(x^3+x^2+2x^2+x+2+1)=\\\\\\(x-1)(x^3+3x^2+x+3) =\\\\\\(x-1)( \underline{(x+3)}x^2+\underline{(x+3)})=(x^2+1)\underbrace{(x-1)(x+3)}_{x^2+2x-3}= \\\\\\(x^2+1)(x^2+2x-3) : (x^2+2x-3)=x^2+1

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Which number line model of the sum of 8 + -12 correctly ​
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Answer:

U did not add a picture but if u do I will help.

Step-by-step explanation:

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hichkok12 [17]

Answer:

See the procedure

Step-by-step explanation:

we know that

<u>The Triangle Inequality Theorem</u>, states that the sum of the lengths of any two sides of a triangle is greater than the length of the third side

Let

a,b,c the lengths side of triangle

c is the greater side

The perimeter is equal to

P=a+b+c

P=36 cm

If c=18 cm

then

a+b=18

Applying the Triangle Inequality Theorem

a+b > c

18 > 18  ----> is not true

therefore

Principal Aranda is incorrect

The larger side cannot measure 18 cm

The largest side must be less than 18 cm

3 0
3 years ago
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