Question

The lengths of the diagonals of a rhombus are 18 cm and 24 cm. What is its perimeter and what is the distance between the parallel sides?
I don't know the distance but the perimeter is 60cm

Answer 1

Answer:

Perimeter = 60 cm

Distance between the parallel sides = 14.4 cm

Step-by-step explanation:

In the given rhombus ABCD,  AC = 24 cm and BD = 18 cm

As we know in a rhombus BC² = OB² + OC²

BC² = (18/2)²+ (24/2)² = 9² + 12² = 81 + 144 = 225

BC = √225 = 15 cm.

So perimeter of the rhombus = 4×15 = 60 cm

Area of rhombus = (1/2)×Multiplication of diagonals = (1/2)×18×24 = 216 cm²

And from the given diagram area of rhombus ABCD = 2×area of ΔABD

= 2×(1/2)×BC×BE = BC×BE = 15×BE

Since area of rhombus is 216 cm², therefore

15×BE = 216

BE = 216/15 = 14.40 cm

Therefore the distance between two parallel lines is 14.40 cm.

Answer 2

Try this option:
note, that distance between the parallel sides is shown via formula of area.
If it is possible, check the arithmetic.