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grin007 [14]
3 years ago
13

Jenna can paint the shed in 2 hours. Juan can paint it in 1.5 hours. • Jenna says is they work together the job will take 1/2+1/

1.5=1^1/2 hours. • Juan says if they work together the job will take 2+1.5/2=1^3/4 hours. Determine if either Jenna or Juan is correct. Explain your reasoning with numbers and words.
Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
8 0

Answer:

There is a formula for this:

[Worker 1 Time * Worker 2 Time] / [Worker 1 Time + Worker 2 Time]

[2 * 1.5] / [2 + 1.5] = 3.0 / 3.5

= 0.8571428571 Hours =

51.43 minutes

Both Jenna and Juan are INCORRECT.

Step-by-step explanation:

Nostrana [21]3 years ago
7 0

Answer:

Step-by-step explanation:

1 job / 2 hours + 1 job / 1.5 hours = 1 job / x  When they work together.

1/2 + 1/1.5 = 1/x                Basic Equation. Change to decimal form

0.5 + 0.6666 = 1/x          Add like terms on the left

1.1666666 = 1/x              Multiply by x on both sides.

1.1666667 x = 1               Divide by 1.16666667

x = 1 / 1.166667               Do the division.

x = 0.8571428              

x = 6/7 of an hour.

This kind of question will <em>always</em> produce an answer that is less than the smallest number.

So the answer must be smaller than 2 hours or 1.5 hours.

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3 years ago
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dusya [7]

Answer:

F=\frac{s^2_2}{s^2_1}=\frac{5.5}{2.5}=2.2

Now we can calculate the p value but first we need to calculate the degrees of freedom for the statistic. For the numerator we have n_2 -1 =16-1=15 and for the denominator we have n_1 -1 =16-1=15 and the F statistic have 15 degrees of freedom for the numerator and 15 for the denominator. And the P value is given by:

p_v =2*P(F_{15,15}>2.2)=0.138

For this case the p value is highert than the significance level so we haev enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviations are not significantly different

Step-by-step explanation:

Information given

n_1 = 16 represent the sampe size 1

n_2 =16 represent the sample 2

s^2_1 = 2.5 represent the sample deviation for 1

s^2_2 = 5.5 represent the sample variance for 2

\alpha=0.10 represent the significance level provided

The statistic is given by:

F=\frac{s^2_2}{s^2_1}

Hypothesis to test

We want to test if the variations in terms of the variance are equal, so the system of hypothesis are:

H0: \sigma^2_1 = \sigma^2_2

H1: \sigma^2_1 \neq \sigma^2_2

The statistic is given by:

F=\frac{s^2_2}{s^2_1}=\frac{5.5}{2.5}=2.2

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p_v =2*P(F_{15,15}>2.2)=0.138

For this case the p value is highert than the significance level so we haev enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviations are not significantly different

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Hello!

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Have a nice day!

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