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Gala2k [10]
4 years ago
6

Eight percent of a population shows a recessive trait. What would be the frequency of the heterozygotes for that trait if the po

pulation is in hardy=w
Biology
1 answer:
laiz [17]4 years ago
3 0

Population that show recessive trait should be only homozygous recessive. If the population in Hardy Weinberg equilibrium, then the recessive trait gene frequency would be:

homozygous recessive = aa= 8%=0.08

a= √0.08=0.283


a+A=1

A= 1-a = 1- 0.283= 0.717


The percentage of heterozygote in population would be:

heterozygote= 2 Aa= (2) (0.717) ( 0.283)= 0.4058= 40.58%

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