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Anettt [7]
4 years ago
10

How is ammonia “nitrified”

Physics
1 answer:
hichkok12 [17]4 years ago
4 0

Answer:

ammonia can be produced at ambient pressure from, air water and concentrated sunlight as a renewable source of process heat via nitrogen reduction with a looped metal nitride followed by separate hydrogenation of the lattice nitrogen into ammonia

Explanation:

nitride redox materials for solar driven ammonia systhesis

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A charge of +1 coulomb is place at the 0 cm mark of a meter stick. A charge of +4 coulombs is placed at the 100 cm mark of the s
UkoKoshka [18]

As per the question the charge of one coulomb is at 0 cm of the metre stick.the second charge of 4 coulomb is situated at at 100 cm of metre stick.

hence the separation distance between them is 100 cm.

now as per the question a proton is set up  between them in such a way that the net force on it is zero

let the charge of proton is q coulomb let the proton is situated at distance of x cm from the charge 1 coulomb.hence it is situated at a distance of 100-x cm from the charge 4 coulomb.

the force exerted by 1 coulomb on proton is-\frac{1}{4\pi\epsilon} \frac{1*q}{x^2}

the force exerted by 4 coulomb on proton is-\frac{1}{4\pi\epsilon} \frac{q*4}{[100-x]^2}

as the net force is zero,hence-

\frac{1}{4\pi\epsilon} \frac{1*q}{x^2}=\frac{1}{4\pi\epsilon} \frac{4*q}{[100-x]^2}

=\frac{1}{x^2} =\frac{4}{[100-x]^2}


x^2=\frac{[100-x[^2}{4}[/tex[tex]x=\frac{100-x}{2}

3x=100

x=\frac{100}{3}

=33.33333cm   [ans]







4 0
3 years ago
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A 0.0750kg teddy bear is dropped from a deck that is 3.00m above the ground. What will be the velocity of the teddy bear as it s
FrozenT [24]

The velocity of the teddy bear as it strikes the ground is 7.67 m/s.

<h3>Velocity of the teddy when it strikes the ground</h3>

The velocity of the teddy when it strikes the ground is calculated from principle of conservation of energy as shown below.

K.E(bottom) = P.E(top)

¹/₂mv² = mgh

v² = 2gh

v = √2gh

where;

  • h is height of fall of the teddy
  • g is acceleration due to gravity

v = √(2 x 9.8 x 3)

v = 7.67 m/s

Thus, the velocity of the teddy bear as it strikes the ground is 7.67 m/s.

Learn more about conservation of energy here: brainly.com/question/166559

#SPJ1

4 0
2 years ago
An antacid blank excess stomach acid.
Fynjy0 [20]
What are you asking?
3 0
3 years ago
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If an object travels around a 200m long track in 2 seconds what is the objects speed and velocity?
Snowcat [4.5K]

Answer:100m/s

Explanation:

in this question it does not specify the direction for a vector quantity .so in this question the velocity and the speed is considered the same.

Speed=d/t=200/2=100m/s

6 0
4 years ago
a person is moving for 2 minutes with a constant speed of 4 m/s how far of a distance would the person cover
Makovka662 [10]
Speed=distance÷time so distance=speed×time therefore distance=4×2 which is 8.
8 0
4 years ago
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