To make 2 molecules of water, you need 2 molecules of hydrogen plus 1 molecule of oxygen. If I have unlimited amounts of oxygen
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Concept: The magnification of spherical mirror can be defined by two ways.
(i) In terms of the height of the object and image.
The magnification of the spherical mirror is defined as the ratio of the height of the image'' to the height of the object '
'. It is denoted by letter 'm'.
Mathematically, it can be written as
(ii) In terms of the object's and image's distances.
The magnification of the spherical mirror is defined as the negative ratio of the image distance'' to the object distance '
'.
Mathematically, it can be written as
Now, from equation (1) and (2) we have,
Given: Spherical Concave Mirror,
We will consider positive sign for object's and image's distance because both are in front of the mirror.
Object distance .
Image distance
Object's height
Image's height
Now, apply equation (3)
Or, hi = - 8 mm
Here; negative sign means, the image will be inverted.
The image's height will be 8 mm.
Answer:
The ratio of the orbital time periods of A and B is
Solution:
As per the question:
The orbit of the two satellites is circular
Also,
Orbital speed of A is 2 times the orbital speed of B
(1)
Now, we know that the orbital speed of a satellite for circular orbits is given by:
where
R = Radius of the orbit
Now,
For satellite A:
Using eqn (1):
(2)
For satellite B:
(3)
Now, comparing eqn (2) and eqn (3):
For E = 200 gpa and i = 65. 0(106) mm4, the slope of end a of the cantilevered beam is mathematically given as
A=0.0048rads
<h3>What is the slope of end a of the cantilevered beam?</h3>Generally, the equation for the is mathematically given as
Therefore
A=\frac{10+10^2+3^2}{2*240*10^9*65*10^6}+\frac{10+10^3*3}{240*10^9*65*10^{-6}}
A=0.00288+0.00192=0.0048rads
A=0.0048rads
In conclusion, the slope is
A=0.0048rads
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