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Vlad [161]
3 years ago
15

To make 2 molecules of water, you need 2 molecules of hydrogen plus 1 molecule of oxygen. If I have unlimited amounts of oxygen

but only 4 grams of hydrogen, how much water could I make?
Physics
1 answer:
Semenov [28]3 years ago
5 0
Hey there,

So first we need to know how much molecules are there in 4 grams of hydrogen right?
In one gram of hydrogen there are 6.0221415 multiplied by 10^25 molecules right?(this number is known as avagadors constant )

And to make one molecule of water u need two molecules of hydrogen and one of oxygen.
And oxygen is unlimited right?

So when we have 6.0221415 grams of hydrogen tow if these are required to make one water.
So divide that by two and you get 3.0110704 multiplied by 10^25.
So the answer is you can make the above number of water molecules.

Hope this helps!!!
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What do you understand by waves. what is the equation?
kipiarov [429]
A wave is a perturbation in a material from the point the perturbation was produced, to the sorrounding area

5 0
3 years ago
What an object is placed 8 mm from a concave spherical mirror a clear image can be projected on the screen 16 mm in front of me
alexgriva [62]

Concept: The magnification of spherical mirror can be defined by two ways.

(i) In terms of the height of the object and image.

The magnification of the spherical mirror is defined as the ratio of the height of the image'h_{i}' to the height of the object 'h_{o}'. It is denoted by letter 'm'.

Mathematically, it can be written as

m= \frac{h_{i}}{h_{o}}   ------------(1)

(ii) In terms of the object's and image's distances.

The magnification of the spherical mirror is defined as the negative ratio of the image distance'd_{i}' to the object distance 'd_{o}'.

Mathematically, it can be written as

m= - \frac{d_{i}}{d_{o}}   ------------(2)

Now, from equation (1) and (2) we have,

m = \frac{h_{i}}{h_{o}}   = -  \frac{d_{i}}{d_{o}}  -----------(3)

Given: Spherical Concave Mirror,

We will consider positive sign for object's and image's distance because both are in front of the mirror.

Object distance (d_{o}) = + 8 mm.

Image distance (d_{i}) = + 16 mm

Object's height (h_{o}) = + 4 mm

Image's height (h_{i}) =?

Now, apply equation (3)

\frac{h_{i}}{h_{o}}   = - \frac{d_{i}}{d_{o}}

Or,   \frac{h_{i}}{4 mm}   = - \frac{+16 mm}{+8 mm}

Or, hi = - 8 mm

Here; negative sign means, the image will be inverted.

The image's height will be 8 mm.

4 0
3 years ago
Two satellites, A and B are in different circular orbits
jek_recluse [69]

Answer:

The ratio of the orbital time periods of A and B is \frac{1}{2}

Solution:

As per the question:

The orbit of the two satellites is circular

Also,

Orbital speed of A is 2 times the orbital speed of B

v_{oA} = 2v_{oB}        (1)

Now, we know that the orbital speed of a satellite for circular orbits is given by:

v_{o} = \farc{2\piR}{T}

where

R = Radius of the orbit

Now,

For satellite A:

v_{oA} = \farc{2\piR}{T_{a}}

Using eqn (1):

2v_{oB} = \farc{2\piR}{T_{a}}           (2)

For satellite B:

v_{oB} = \farc{2\piR}{T_{b}}              (3)

Now, comparing eqn (2) and eqn (3):

\frac{T_{a}}{T_{b}} = \farc{1}{2}

6 0
3 years ago
Determine the slope of end a of the cantilevered beam. E = 200 gpa and i = 65. 0(106) mm4
DENIUS [597]

For E = 200 gpa and i = 65. 0(106) mm4,  the slope of end a of the cantilevered beam  is mathematically given as

A=0.0048rads

<h3>What is the slope of end a of the cantilevered beam?</h3>

Generally, the equation for the   is mathematically given as

A=\frac{PL^2}{2EI}+\frac{ML}{EI}

Therefore

A=\frac{10+10^2+3^2}{2*240*10^9*65*10^6}+\frac{10+10^3*3}{240*10^9*65*10^{-6}}

A=0.00288+0.00192=0.0048rads

A=0.0048rads

In conclusion,  the slope is

A=0.0048rads

Read more about Graph

brainly.com/question/14375099

5 0
2 years ago
Three charges are on a line. A positive charge is on the far left labeled q Subscript 1 baseline positive 6 Coulombs. The second
tiny-mole [99]

Answer:

–1.1 × 10^11 N

Explanation:

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