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kvasek [131]
3 years ago
14

Pls need this last thing due also 9/24/18

Mathematics
1 answer:
AlexFokin [52]3 years ago
3 0

14

a.4 feet

b.4 feet per second

c. positive

d.?

15.teal

16.-5


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Write an inequality that expresses the range in the volume of acceptable tennis balls.
Rudik [331]

Answer:

the smallest number is the lower bound and the largest number is the upper bound, your inequality would be

8.2 ≤ x ≤ 9.5, where x represents the volume of tennis balls.

4 0
3 years ago
David's bedroom door is 8 feet tall and 4 feet wide. A new door would cost $8.00 per square foot. How much would a new bedroom d
Verdich [7]

Answer:

$ 256

Step-by-step explanation:

square footage of door =   8 x 4 = 32 ft^2

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2 years ago
A movie club offers two plans. Plan A charges $40 to sign up for the plan and $8 for each movie ticket. Plan B charges $67 to si
Travka [436]

Answer:

9

Step-by-step explanation:

X=Tickets bought

A=$40+$8x

B=$67+$5x

After 1 ticket bought it would be:

A=$48

B=$72

After 9 tickets bought:

A=$112

B=$112

From this you can see that Plan B is better for ones who would see 9+ movies as the recurring price would be lower. If you would only go to watch a couple movies, Plan A would be better.

3 0
4 years ago
Read 2 more answers
6.1.3
Nata [24]

Answer:

The requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.

Step-by-step explanation:

A normal-distribution is an accurate symmetric-distribution of experimental data-values.  

If we create a histogram on data-values that are normally distributed, the figure of columns form a symmetrical bell shape.  

If X \sim N (µ, σ²), then Z=\frac{X-\mu}{\sigma}, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z \sim N (0, 1).

The distribution of these z-variates is known as the standard normal distribution.

Thus, the requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.

8 0
3 years ago
Can someone help please
sergey [27]
The answer is  12.65 , your welcome
3 0
3 years ago
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