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motikmotik
4 years ago
12

A rectangular prism has a length of 212 m, a width of 4 m, and a height of 214 m. what is the volume of the prism?

Mathematics
1 answer:
OLga [1]4 years ago
4 0
Area of rectangle * height of prism
4*214*212
181,472
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strojnjashka [21]

Answer:

D. x=3

Step-by-step explanation:

6 0
3 years ago
Round 8070 to the nearest thousand
enot [183]

Answer:8000

Step-by-step explanation:

Here's the general rule for rounding: If the number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up. Example: 38 rounded to the nearest ten is 40. If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down.

6 0
3 years ago
A cube is shown below.What is the lateral surface area of the cube?
disa [49]

The lateral surface area is the surface area of the cube excluding the base and the top, which would make 4 square planes.

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4 1/2 x 4 1//2

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Hope it helps!


3 0
3 years ago
△ABC is an isosceles triangle with legs AB and AC. △AYX is also an isosceles triangle with legs AY and AX. The proof that △ABC ~
Maslowich

Answer with explanation:

Given:  △ABC is an isosceles triangle with legs AB and AC.Also, △A Y X is also an isosceles triangle with legs A Y and AX.

To Prove: △ABC ~ △A Y X

Proof with Statement

1. △ABC is isosceles with legs AB and AC; △A Y X is also isosceles with legs A Y and AX.

2.AB ≅ AC and A Y ≅ AX.→definition of isosceles triangle

3.AB = AC and A Y = AX →→ definition of Congruency.

4.→→A Y × AC=AX × AC⇒[Multiplication property of equality]

5.≡A Y × AC=AX × AB⇒[Substitution property of equality]

6.\rightarrow\frac{AB}{AY}=\frac{AC}{AX}

----------------[Division property of equality]

7.Also, ∠A is common angle between two triangles.That is,

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⇒Missing statement and Reason in the entire proof.

8.△ABC ~ △AYX----[SAS]

6 0
3 years ago
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Pls help sin(x)/1- cos(x) - cot(x) = csc(x)​
MrRa [10]

\text{LHS}=\frac{\sin x}{1-\cos x}-\cot x\\\\=\frac{\sin x}{1-\cos x}-\frac{\cos x}{\sin x}\\\\=\frac{\sin^{2} x}{\sin x(1-\cos x)}-\frac{\cos x(1-\cos x)}{\sin x(1-\cos x)}\\\\=\frac{\sin^{2} x-\cos x(1-\cos x)}{\sin x(1-\cos x)}\\\\=\frac{\sin^{2} x-\cos x+\cos^{2} x}{\sin x(1-\cos x)}\\\\=\frac{(\sin^{2} x+\cos^{2} x)-\cos x}{\sin x(1-\cos x)}\\\\=\frac{1-\cos x}{\sin x(1-\cos x)}\\\\=\frac{1}[\sin x}\\\\=\csc x\\\\=\text{RHS}

3 0
2 years ago
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