The volume of a pyramid with known base area and height is 1/3 of the volume of a box with those same dimensions. So
Follow the order of operations. PEMDAS. Parenthesis, Exponents, Multiplication, Division, Addition, and Subtraction. Let's start with parenthesis. First we so everything inside the parenthesis. So the first thing we do, is exponents, 2 x 2 = 4. Now the top equation is 3 x 4 - 23. Next thing in the order of operations, is Multiplication. So now we do 3 x 4. Which equals 12. Now the top equation is 10 - 12 - 23. Now we do Subtraction in order. First 10 - 12 = negative 2 (-2) Then we do -2 - 23 which equals negative 25 (-25). Now let's work on the bottom equation. Once again follow the order of operations. We do the exponents in the parenthesis first. 10 x 10 = 100. Then do the rest in the parenthesis, 1 + 100 = 101. Now the exponents in the outside of the parenthesis. - 2 x - 2 = 4. And 5 x 5 = 25. Then we do Multiplication, 4 x 25, which equals 100. Then we do 101 - 100 = 1. Then we reduce the fraction. -25/1 = -25. Therefore the answer to your problem is -25. I apologize for taking so long to write this. Hope this helps though!
-Twixx
Answer:
D) 1
Step-by-step explanation:
When you start raising i to certain powers, you begin to notice a pattern.
This cycle repeats forever. Since 84 is a multiple of 4, i^84 must be 1. Hope this helps!
Answer:
9 a (5 x^2 + 3 x + 2)
Step-by-step explanation:
Simplify the following:
45 a x^2 + 27 a x + 18 a
Factor 9 a out of 45 a x^2 + 27 a x + 18 a:
Answer: 9 a (5 x^2 + 3 x + 2)
<u>Answer-</u>
<em>The total amount of water wasted this year is 6716 gallons.</em>
<u>Solution-</u>
A study indicated that the citizens of Morris-town wasted 5840 gallons of water last year.
This year they wasted 15% more than that amount they wasted previous year.
15% of 5840 is,
The total amount of water wasted this year =
The amount of water wasted previous year + 15% more of the amount of that
= 5840 + 876
= 6716 gallons
Therefore, the total amount of water wasted this year is 6716 gallons
