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jasenka [17]
3 years ago
15

A freight train made a trip to a repair. On the trip there it travelers 25 mph and on the return trip it went 20 mph. How long d

id there take if the return trip took 15 hours?
Mathematics
1 answer:
Sophie [7]3 years ago
5 0

Answer:

Time taken by train in onward journey = 12 hours.

Step-by-step explanation:

Given:

Speed of train making a trip to a repair = 25 mph

Speed of train on return trip = 20 mph

Time taken for return trip = 15 hours

To find the time taken on the on wards trip.

Solution:

The distance traveled by the train on the trip and return trip is the same as the y are of same trips in opposite directions.

Distance can be calculated by using the data for the return trip.

Distance= Speed\times Time

Distance= 20\ mph\times 15\ h=300\ miles

Speed of train for on ward trip = 25 mph

Time taken = \frac{Distance}{Speed}

Time taken = \frac{300\ miles}{25\ mph}= 12\ h

Thus, time taken by train in onward journey = 12 hours.

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Answer:

3.05 or 31/2 pounds

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Step-by-step explanation:

To find the total weight all the weights have to have the same units of measurements

It is either pounds is converted to ounces or ounces is converted to pounds

1. convert ounces to pound

1 ounce = 0.0625

12 ounces = 0.0625 x 12 = 0.75 pounds or 3/4

add together = 1 1/2 + 3/4 + 1 1/4 = 1\frac{1}{2} + \frac{3}{4}  + 1\frac{1}{4}

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6 0
3 years ago
Circle the expression(s) that give the same product as 6 x 3/8.
34kurt

Answer:

(6 × 3) divided by 8 and 3/8 × 6

Step-by-step explanation:

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9514 1404 393

Answer:

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Step-by-step explanation:

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<em>Alternate solution</em>

We observe that the difference between the upper segment lengths is ...

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