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alexdok [17]
3 years ago
11

What is the sum of the numbers in the series? 15 + 11 + 7 + . . . + (–129)

Mathematics
1 answer:
babymother [125]3 years ago
3 0
Using Gauss's method
Total number of terms = [15-(-129)]/4+1=36+1=37
Add
S=15+11+7+....-125-129
S=-129-125-...+7+11+15
--------------------------------
2S=-114-114-114...(37 times)
=>
sum=S=(1/2)*(-114)*37=-2109


Using AP, T(n)=15+11+7+....-129
T(n)=19-4n  => T(1)=15, T(37)=-129
S(n)=(1/2)(37)(T(1)+T(37)=(1/2)37(15-129)=2109
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Step-by-step explanation:

Here, the total number of T/F question = 10

The minimum answers needed correctly answered = 8

So, student needs to answer at least 8 questions correctly.

Here, the possibility of answering a question correctly  = (\frac{1}{2})   = p = 0.5

Also, the possibility of answering a question wrong  = (\frac{1}{2})  = q = 0.5

Now, to pass he needs to answer 8 or more (  8 , 9 or 10) answers correctly.

P(answering 8 correct answer)  = ^{10}C_8(p)^8(q)^2 = ^{10}C_8(0.5)^8(0.5)^2  = 0.0439

P(answering 9 correct answer)  =  ^{10}C_9(p)^9(q)^1 = ^{10}C_9(0.5)^9(0.5)^1  = 0.0097

P(answering 10 correct answer)  = ^{10}C_{10}(p)^{10}(q)^0 = ^{10}C_{10}(0.5)^{10}(0.5)^0  = 0.00097

So, the total Probability   = P(8) + P(9) + P(10)

= (0.0439) + (0.0097) + (0.00097)

= 0.05457

Hence, the probability that the student passes the quiz  with  at least 8 of the questions correct is 0.05457.

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