Answer:
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Step-by-step explanation:
Find the nth term of this number sequence.
2 8 14 20 26
Again write the numbers 1 to 5 above the numbers in the sequence, and leave a spare line again.
n 1 2 3 4 5 (1st row)
(2nd row)
2 8 14 20 26 (3rd row)
Since the sequence is going up by 6, write down your multiples of 6 on the 2nd row.
n 1 2 3 4 5 (1st row)
6n 6 12 18 24 30 (2nd row)
2 8 14 20 26 (3rd row)
Now, to get the numbers in the 3rd row from the 2nd row take off 4.
So, to get from the position numbers (n) to the numbers in the sequence you have to times the position numbers by 6 and take off 4.
Therefore, the nth term = 6n – 4
Answer:
It took 2.5 (2 and a half) minutes to fill up one tire
Step-by-step explanation:
Hope this helps :)
Rahul use addition property of equality in step 2.
Solution:
The image of the question is attached below.
Step 1:
combine like terms together.
To make the denominator same multiply and divide 2x by 5.
Step 2:
By addition property of equality, add 
on both side of the equation.
Step 3:
Step 4:
Multiply by 
on both side of the equation.
Hence Rahul use addition property of equality in step 2.
