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omeli [17]
3 years ago
12

What is 3/48 in simplist form?

Mathematics
2 answers:
AlexFokin [52]3 years ago
7 0
As 48 is a multiple of 3 you can cancel the fraction so it is 1/?
48/3 = 16
1/16 in its simplest form
luda_lava [24]3 years ago
3 0

divide top and bottom by 3 to make 1/16
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What are the x-intercepts of the graph y=f(x+4)
Sergio [31]
The graph is y=x+4, to get the x-intercept we let y=0; and solve for x
thus we shall have:
0=x+4
subtract 4 from both sides
0-4=x+4-4
-4=x
hence the x-intercept will be at point (-4,0)


5 0
3 years ago
A right circular cylinder with a radius of 2.3cm and a height of 1.4cm has a total surface area of ​
likoan [24]

Answer:

i think 6.44

Step-by-step explanation:

first the diameter is 4.6 then multiply the 4.6 with 1.4 and u obtaine 6.44 (note:iam not sure iam still in seven grade)

4 0
3 years ago
Todd buys 3 CDs at $16.99 each and a DVD that costs $24.99. He pays
VikaD [51]

Answer:

$24.04

Step-by-step explanation:

3 x $16.99 = $50.97

1 x $24.99 = $24.99

$24.99 + $50.97 = $75.96

$100 - $75.96 = $24.04

5 0
3 years ago
Read 2 more answers
Plz plz help<br>I've been stuck on this since yesterday
Vanyuwa [196]

y=ax+b

then

-9= -9a+b

0= -6a+b


a=3 and b=18


y=3x+18

7 0
3 years ago
Read 2 more answers
A rectangular box is to have a square base and a volume of 20 ft3. If the material for the base costs $0.35 per square foot, the
denpristay [2]

Answer:

Length = 2 ft

Width = 2 ft

Height = 5 ft

Step-by-step explanation:

Let the square base of the box has one side = x ft

Therefore, area of the base = x² ft²

Cost of the material to prepare the base = $0.35 per square feet

Cost to prepare the base = $0.35x²

Let the height of the box = y ft

Then the volume of the box = x²y ft³ = 20

y=\frac{20}{x^{3} } -----(1)

Cost of the material for the sides = $0.10 per square feet

Area of the sides = 4xy

Cost to prepare the sides of the box = $0.10 × 4xy

                                                             = $0.40xy

Cost of the material to prepare the top = $0.15 per square feet

Cost to prepare the top = $0.15x²

Total cost of the box = 0.35x² + 0.40xy + 0.15x²

From equation (1),

Total cost C=0.35x^{2}+(0.40x)\times \frac{20}{x^{2} }+0.15x^{2}

C=0.35x^{2}+\frac{8}{x}+0.15x^{2}

C=0.5x^{2}+\frac{8}{x}

Now we take the derivative of C with respect to x and equate it to zero,

C'=0.5(2x)-\frac{8}{x^{2}} = 0

x-\frac{8}{x^{2}}=0

x=\frac{8}{x^{2} }

x^{3}=8

x = 2 ft.

From equation (1),

(2)^{2}y=20

4y = 20

y = 5 ft

Therefore, Length and width of the box should be 2 ft and height of the box should be 5 ft for the minimum cost to construct the rectangular box.

8 0
3 years ago
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