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3241004551 [841]
3 years ago
7

What is the VALUE OF X, for question one? Show work if possible

Mathematics
1 answer:
andrew-mc [135]3 years ago
5 0
In a parallelogram, the diagonals bisect each other.

Therefore, x = 15.
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Which of the following best describes /JKL?<br> 32°<br> L<br> K
Alex777 [14]

The best statement that describes the angle JKL is inscribed angle.

<h3>What is an inscribed angle?</h3>

An inscribed angle in a circle is formed by two chords that have a common end point on the circle. The chord JK and LK intersect in the circle.

The angle ∠JKL is not an obtuse angle because it's less than 90 degrees.

The angle ∠JKL is not a vertical angle because it's not vertically opposite  any angle.

The angle ∠JKL is not a central angle because it was not from from the centre of the circle.

The angle is an inscribed angle because it was formed by the intersection of two chords in the circle.

learn more on angles here: brainly.com/question/6563602

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7 0
2 years ago
A chord is 5 inches from the center of a circle whose diameter is 26 inches. What is the number of centimeters in the length of
lilavasa [31]
First of all, sorry for not including a picture - I hope I can describe this well enough:

Call the centre of the circle O, the chord AB (touching the circumference at A and B) and the midpoint of AB M. From circle theorems, we know that a radius, passing through the midpoint of a chord, will be perpendicular to it. Therefore we have a right-angled triangle OMA, with the hypotenuse OA forming the radius of length 13in, the line OM being 5in as stated in the question, and the side AM being an unknown.

By Pythagoras' theorem, AM = <span>√(13^2 - 5^2) = 12in (it's a 5,12,13 Triple)

Because M is the midpoint of AB, this value needs to be doubled to get the length of AB as 24in. One inch is 2.54cm (3sf), so the length of the chord is:

24 * 2.54 = 60.96cm, which rounds to 61.0cm (3sf)

I hope this helps
</span>
6 0
4 years ago
What expression shoes a way to find 6*1295
vova2212 [387]

Answer:

halo <em>s</em><em>a</em><em>y</em><em>a</em><em> </em><em>1</em><em>3</em><em> </em><em>_</em><em>6</em><em>7</em><em>÷</em><em>1</em><em>2</em><em> </em><em>9</em><em>0</em><em>=</em><em>5</em><em>6</em><em>÷</em><em>4</em><em>0</em><em> </em><em>6</em><em>*</em><em>1</em><em>2</em><em>9</em><em>5</em><em> </em><em>/</em><em>4</em><em> </em><em>=</em><em>1</em><em>2</em>

6 0
3 years ago
Read 2 more answers
163.89 to the hundreds place
saw5 [17]
Answer: 200

Explanation: 348
                     / | \
        Hundred |  \
                Tens   \
                   Single

163.89 + 36.11  = 200
163.89 - 63.89  = 100
                 |
                 |
What is the lowest number (Not including +/- sign before it)

Answer: 1st one/36.11

<span>Final answer (what you put on paper): 100</span>
6 0
4 years ago
What is the probability that a class of 50 has an average midterm mark that is less than 75?
Vika [28.1K]

The probability that a class of 50 has an average midterm mark that is less than 75 is value=0

Average is the mathematics mean, and is calculated by means of adding a group of numbers and then dividing with the aid of the count of these numbers. for instance, the average of 2, three, three, five, 7, and 10 is 30 divided with the aid of 6, that is five.

The common is described as the implied value that is identical to the ratio of the sum of the number of a given set of values to the whole wide variety of values gift within the set.

There are three primary sorts of common: imply, median, and mode. each of those techniques works slightly differently and frequency effects in barely specific regular values. The suggestion is the maximum normally used average. To get the suggested fee, you add up all of the values and divide this total by using the number of values.

The probability that a class of 50 has an average midterm mark that is less than 75

n = 50

P(<75)=P(Z<75)

P(Z<75−786√50)

P(Z<−3.5355)

We will look for the value in the StandardNormal able. We will get the value=0

Learn  more about average here brainly.com/question/20118982

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6 0
1 year ago
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