19191020202929293994494944
        
             
        
        
        
Check the picture below.
so... you can pretty much see how long RS and QT are, you can just count the units off the grid.
now, let's find QR's length

and let's also find the length for ST

so, add the lengths of all sides, and that's the perimeter of the trapezoid.
 
        
        
        
Drawing it out, as seen, using the Pythagorean theorem we get that w^2+l^2 (with w=width and l=length)=diagonal^2=24^2+l^2=40^2. Subtracting 24^2 from both sides, we get 40^2-24^2=l^2=1024. Square rooting both sides, we get l=32. Since the perimeter is 2w+2l, we get 32*2+24*2=64+48=112
 
        
        
        
Answer:
<h2><u><em>
True</em></u></h2>
Step-by-step explanation:
a = a (true)
2 = 2 (true)
 
        
                    
             
        
        
        
9514 1404 393
Answer:
   x = 10; WX = 5; HJ = 10
Step-by-step explanation:
The hash marks indicate that points W and X are midpoints of their respective segments. That makes WX a midline of the triangle. The midline is always half the length of the base (HJ). We can use this fact to write an equation relating the lengths.
   HJ = 2·WX
   x = 2(x -5) . . . .substitute the given expressions
   x = 2x -10 . . . . eliminate parentheses
   10 = x . . . . . . . add 10-x to both sides
This value of x tells you that ...
   HJ = x = 10
   WX = x -5 = 5