DH/dt=k(68-H)
1/(68-H)dH=kt assuming k is a constant
ln|68-H|=kt+C (*)
we have all H satisfying (*)
Answer:
15
Step-by-step explanation:
Complementary angles add to 90 degrees
8x+27 + 6x-21 = 90
Combine like terms
14x+6 = 90
Subtract 6 from each side
14x+6-6 = 90-6
14x = 84
Divide by 14
14x/14 = 84/14
x=6
We want angle B
B = 6x-21 = 6*6-21 =36-21 = 15
Answer:
2 1/5
2 X 5 + 1 = 11/5
11/5 X 2/1 = 22/5
1 3/4
1 X 4 + 3 = 7/4
7/4 X 2/1 = 14/4
22/5 + 14/4
5 X 4 = 20
4 X 22 = 88
5 X 14 = 70
88/20 + 70/20 = 158/20
20 goes into 158 7 times with 18 left over
7 18/20 simplified = 7 9/10
Answer:
20/40 = 10/20 = 1/2, 1:2
Step-by-step explanation:
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