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galben [10]
4 years ago
15

Judy bought a coat at a 20% discount sale for $72. what was thw original price of the coat

Mathematics
1 answer:
Rama09 [41]4 years ago
6 0
The original price of the coat is $90
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Using the digits 0-9, at most only one time each, fill in the boxes to
ycow [4]

Answer:

2 * 3 + 4 * 5 = 26

5 * 7 + 1 * 8 = 43

Step-by-step explanation:

Given

_ * _ + _ * _ = _ _

Required

Fill in the boxes with digits 0 to 9

From the question we understand that the result must be two digits i.e. _ _

To solve this, we'll make use of trial by error method:

Fill the first two boxes wit 2 and 3: _ * _ becomes 2 * 3

Fill the next two boxes with 4 and 5: _ * _ becomes 4 * 5

So,we have

2 * 3 + 4 * 5

6 + 20

26

Hence, the first combination is 2 * 3 + 4 * 5 = 26

Another possible combination is:

Fill the first two boxes wit 5 and 7: _ * _ becomes 5 * 7

Fill the next two boxes with 1 and 8: _ * _ becomes 1 * 8

So,we have

5 * 7 + 1 * 8

35 + 8

43

Hence, another combination is 5 * 7 + 1 * 8 = 43

<em>Note that; there are more possible combinations</em>

7 0
3 years ago
If (ax+2)(bx+7)=15x2+cx+14 for all values of x, and a+b=8, what are the 2 possible values fo c
dolphi86 [110]

Given:

(ax+2)(bx+7)=15x^2+cx+14

And

a+b=8

Required:

To find the two possible values of c.

Explanation:

Consider

\begin{gathered} (ax+2)(bx+7)=15x^2+cx+14 \\ abx^2+7ax+2bx+14=15x^2+cx+14 \end{gathered}

So

\begin{gathered} ab=15-----(1) \\ 7a+2b=c \end{gathered}

And also given

a+b=8---(2)

Now from (1) and (2), we get

\begin{gathered} a+\frac{15}{a}=8 \\  \\ a^2+15=8a \\  \\ a^2-8a+15=0 \end{gathered}a=3,5

Now put a in (1) we get

\begin{gathered} (3)b=15 \\ b=\frac{15}{3} \\ b=5 \\ OR \\ b=\frac{15}{5} \\ b=3 \end{gathered}

We can interpret that either of a or b are equal to 3 or 5.

When a=3 and b=5, we have

\begin{gathered} c=7(3)+2(5) \\ =21+10 \\ =31 \end{gathered}

When a=5 and b=3, we have

\begin{gathered} c=7(5)+2(3) \\ =35+6 \\ =41 \end{gathered}

Final Answer:

The option D is correct.

31 and 41

8 0
1 year ago
Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!
nika2105 [10]
56.7!!!!!!!!!!!!!!!!!!!!
4 0
3 years ago
Which situation CANNOT be represented by this equation?
fomenos
The second one, because the price of the candle is $4, meaning the equation would have to be 4x+3=19
8 0
3 years ago
In congruent figures, corresponding angles have equal measures. true or false?
algol [13]
This is true

Think of two houses. If we say "the houses are identical" then the corresponding pieces must be the same (eg: the doors must be the same type out of the same material). In this analogy, the houses are the triangles, which are the overall structures. The doors are the angles since they are pieces of the overall structures. This is what CPCTC is saying

CPCTC = Corresponding Parts of Congruent Triangles are Congruent

Once again, the final answer is true.
8 0
4 years ago
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