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larisa [96]
3 years ago
15

paige must leave her house in 80 minutes for an appointment. she wants to watch a movie while she waits. The movie is 1 hours 15

minutes long. Does Paige have enough time to watch the movie​
Mathematics
1 answer:
leva [86]3 years ago
3 0

Answer:

There is enough time because an 1 and 15 minutes is 60+15 which is 735 which is enough time for her to watch

Step-by-step explanation:

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Step-by-step explanation:

to write a line equation we need minimum of two points. basicaly a line is written in the form y=mx+c where, m is the slope of the line and c is the intercept made by the line on x-axis (OR) or if two points (x1,y1) and (x2,y2) are given then we can form a line equation as (y-y1)= (y2-y1)*1/(x2-x1) *x-x1 (OR) (y-y2)= (y2-y1)*1/(x2-x1) *x-x2

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2 years ago
Minutes played points scored
stepan [7]
I think it's A. Sorry if I get it wrong.
7 0
3 years ago
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I need to know of an expression, that also uses an exponent that is equivalent to 5^-3
strojnjashka [21]

Answer:

1/5^3

\frac{1}{5^{3} }

Step-by-step explanation:

I'm not sure how to explain this, but if there is a negative exponent, then it can be written like this, as the denominator of a fraction.

5 0
3 years ago
-y-4=4x<br> put in y=mx+b
marishachu [46]

-y-4=4x\\ \\ -y=4x+4\\ \\ y=-4x-4

<h3>First part of the problem:</h3><h3>-y - 4 = 4x</h3><h3>    + 4   + 4</h3><h3>-y + 0 = 4x + 4</h3><h3>      -y = 4x + 4</h3><h3 />

Hope this helps!

3 0
3 years ago
There are 14 juniors and 16 seniors in a chess club. a) From the 30 members, how many ways are there to arrange 5 members of the
Dmitrij [34]

Answer:

a) 17,100,720

b) 4,717,440

c) 10,920

d) 2821

Step-by-step explanation:

14 juniors and 16 seniors = 30 people

a) From the 30 members, how many ways are there to arrange 5 members of the club in a line?

As it is a ordered arrangement

30.29.28.27.26 = 17,100,720

b) How many ways are there to arrange 5 members of the club in a line if there must be a senior at the beginning of the line and at the end of the line?

16.28.27.26.15 = 4,717,440

c) If the club sends 2 juniors and 2 seniors to the tournament, how many possible groupings are there?

Not ordered arrangement. And means that we need to multiply the results.

C₁₄,₂ * C₁₆,₂

C₁₄,₂ = <u>14.13.12!</u> = <u>14.13 </u>= 91

           12! 2!            2    

C₁₆,₂ = <u>16.15.14!</u> = <u>16.15 </u>= 120

           14! 2!            2    

C₁₄,₂ * C₁₆,₂ = 91.120 = 10,920

d) If the club sends either 4 juniors or 4 seniors, how many possible groupings are there?

Or means that we need to sum the results.

C₁₄,₄ + C₁₆,₄

C₁₄,₄ = <u>14.13.12.11.10!</u> = <u>14.13.12.11 </u>= 1001

                  10! 4!               4.3.2.1    

C₁₆,₄ = <u>16.15.14.13.12!</u> = <u>16.15.14.13 </u>= 1820

                  12! 4!               4.3.2.1    

C₁₄,₄ + C₁₆,₄ = 1001 + 1820 = 2821

7 0
3 years ago
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