This question is incomplete and it also lacks an attached diagram.
Find attached to this answer the appropriate diagram.
Complete Question:
The conditional relative frequency table was generated using data that compared the cost of one ticket for a performance and the method by which the ticket was purchased.
Given that Lorenzo paid more than $30 for a ticket, what is the probability that he purchased the ticket at the box office? Express the answer in decimal form
Answer:
0.14
Step-by-step explanation:
From the attached diagram, we were given a table that contained known values:
The number of tickets that were purchased online we have 2 categories
a) Not more than $30 = 0.7
b) More than $30 = 0.86
The number of tickets that were purchased at the box office also had 2 categories.
a) Not more than $30 = 0.3
b) More than $30 = 0.14
The probability that the ticket Lorenzo paid more than $30 for was purchased at the box office
= P( more than $30 at the box office)
= 0.14
Answer:
C. Both of the above answers
Step-by-step explanation:
13 = -6(-2) + 1
13 = 12 + 1
13 = 13
7 = -6(-1) + 1
7 = 6 + 1
7 = 7
Answer:
3. 150.72 in²
4. 535.2cm²
Step-by-step Explanation:
3. The solid formed by the net given in problem 3 is the net of a cylinder.
The cylinder bases are the 2 circles, while the curved surface of the cylinder is the rectangle.
The surface area = Area of the 2 circles + area of the rectangle
Take π as 3.14
radius of circle = ½ of 4 = 2 in
Area of the 2 circles = 2(πr²) = 2*3.14*2²
Area of the 2 circles = 25.12 in²
Area of the rectangle = L*W
width is given as 10 in.
Length (L) = the circumference or perimeter of the circle = πd = 3.14*4 = 12.56 in
Area of rectangle = L*W = 12.56*10 = 125.6 in²
Surface area of net = Area of the 2 circles + area of the rectangle
= 25.12 + 125.6 = 150.72 in²
4. Surface area of the net (S.A) = 2(area of triangle) + 3(area of rectangle)
= 
Where,
b = 8 cm
h = ![\sqrt{8^2 - 4^2} = \sqrt{48} = 6.9 cm} (Pythagorean theorem)w = 8 cm[tex]S.A = 2(0.5*8*6.9) + 3(20*8)](https://tex.z-dn.net/?f=%20%5Csqrt%7B8%5E2%20-%204%5E2%7D%20%3D%20%5Csqrt%7B48%7D%20%3D%206.9%20cm%7D%20%28Pythagorean%20theorem%29%3C%2Fp%3E%3Cp%3Ew%20%3D%208%20cm%3C%2Fp%3E%3Cp%3E%5Btex%5DS.A%20%3D%20%202%280.5%2A8%2A6.9%29%20%2B%203%2820%2A8%29)
A = L * W
A = 400
L = 4W
400 = 4W * W
400 = 4W^2
400/4 = W^2
100 = W^2
sqrt 100 = W
10 = W.....width is 10 cm
L = 4W
L = 4(10)
L = 40...length is 40 cm
P = 2(L + W)
P = 2(10 + 40)
P = 2(50)
P = 100 <=== perimeter is 100 cm
