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4 years ago

Round $8,546.54 to the nearest $1,000.00

1 answer:

8 0

Its 9,000.00
because it says to the nearest 1,000.00 u look at the 1,000 place which has an 8 sooooo next u look at the number next to 8 which is 5. If its 5 or higher u add 1 to the number 8 but if jts lower than five u leave 8 as it is.In ur case its 5 so u have to make 8 a 9 and replace all other numbers with 0's until decimal point. But in ur question it says round it to nearest 1,000.00 do u have to add 2 zeroes after the decimal.so the answer is 9,000.00

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jeyben [28]

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3 years ago

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3 years ago

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3 years ago

The expressions below model different possibilities for the area of a pool. Identify which of the following expressions have at

Anna007 [38]

<h3>Answer: Choice B is correct</h3>

========================================================

Explanation:

Use a graphing tool like GeoGebra, Desmos, or your graphing calculator to plot each expression given as a separate y equation. Four parabolas should result.

The x intercept is the same as the root or zero of a function.

You should find that only choice B has a root thats larger than 4. That specific root being x = 7.

----------------------------

A non-graphing approach:

You can use the quadratic formula or the factoring method to find the roots.

For choice A, it factors to (x+5)(x+6) = 0. The roots are x = -5 and x = -6 which aren't greater than 4. So we cross choice A off the list. Choices C and D are similar stories.

On the other hand, choice B factors to (x-7)(x+2) = 0 and it has roots of x = 7 and x = -2. This is another way to see why choice B is the answer.

Here are the steps for the quadratic formula for choice B

$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(-5)\pm\sqrt{(-5)^2-4(1)(-14)}}{2(1)}\\\\x = \frac{5\pm\sqrt{81}}{2}\\\\x = \frac{5\pm9}{2}\\\\x = \frac{5+9}{2} \ \text{ or } \ x = \frac{5-9}{2}\\\\x = \frac{14}{2} \ \text{ or } \ x = \frac{-4}{2}\\\\x = 7 \ \text{ or } \ x = -2\\\\$

The quadratic formula is handy in case factoring is either not possible, or guess-and-check is too lengthy of a process. As you can probably tell, we could use the quadratic formula's results to help construct the factored form.

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3 years ago