Answer:
C.I = $1333.85
Step-by-step explanation:
effective interest rode is 
where
i_e efffective rate of interest
i_m = rate of interest = 8%
m = nu,ner of compoundig period per year = 4
t = used for loan time = 2
b)compound interest is given as
![C.I =P[ (1+ \frac{i_m}{m})^{mt}-1]](https://tex.z-dn.net/?f=C.I%20%3DP%5B%20%281%2B%20%5Cfrac%7Bi_m%7D%7Bm%7D%29%5E%7Bmt%7D-1%5D)
we have P-5000 $
i_m -6%
m =2
t = 4
AFTER PUTTING EACH VALUE WE GET
C.I = $1333.85
In this question, it is given that
the product of two numbers is 36 and there GCF is 9.
The formula that relates product of two numbers, GCF and LCM is
Substituting the given values of the product and GCF, we will get
Dividing both sides by 9
Therefore the LCM of the two numbers is 4 .
Answer: The time it takes Jim to drive to the beach is 2 1/8 hours.
Step-by-step explanation:
The amount of time that it takes Pam to drive to the beach is 4 1/4 hours. Converting 4 1/4 hours into improper fraction, it becomes 17/4 hours
Jim can drive to the beach in 1/2 of the times it takes Pam. This means that the time it takes Jim to drive to the beach would be
1/2 × 17/4 = 17/8 hours.
Converting 17/8 hours to mixed fraction, it becomes 2 1/8 hours
Answer:
Yes 5/2 because if you multiply 5/2 by 4 it will give you 10.
Step-by-step explanation:
Multiplication way:
5/2 = 2.5 x
<u>Multiply 4x2.5=10</u>
<u>Multiply 8x2.5=20</u>
Division way:
<u>Divide 10/4=2.5 </u>
<u>Divide 20/8=2.5</u>
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<u>Hope this answer helped.Please give me brainiest.</u>
Answer:
The right option is:
b. There is enough evidence to conclude the mean difference in pulse rates before and after the 5 minute waiting period is different from 0.
Step-by-step explanation:
The null hypothesis is the opposite to the claim that the researchers are trying to prove. In this case, it will state that there is no difference in the mean pulse rates or, in other words, that the mean difference in pulse rates before and after the 5 minute waiting period is 0 (μ=0).
The claim of the researchers, that will be expressed in the alternative hypothesis, is that the mean difference in pulse rates before and after the 5 minute waiting period differs from 0 (μ≠0).
If the null hypothesis is rejected, is because the test shows that there is enough evidence to support the claim that the mean difference in pulse rates before and after the 5 minute waiting period differs from 0 (true alternative hypothesis).
Note: If the null hypothesis wasn't rejected, the conclusion would have been that there is no evidence o support the claim that the mean difference in pulse rates before and after the 5 minute waiting period differs from 0.
The right option is:
b. There is enough evidence to conclude the mean difference in pulse rates before and after the 5 minute waiting period is different from 0.
