There would be a 16% chance of the widgets being defective and there is an 84% chance of the widgets not being defective.
Answer: Yes.
Step-by-step explanation: Each point on the graph has a different X-Value. It's ok for the Y-Values to repeat.
Answer:
14
Step-by-step explanation:
We are given with two
numbers whose first
are same.
It is given that their sum is ![123422](https://tex.z-dn.net/?f=123422)
adding the last two corresponding digits gives,
![0+2=2\\1+1=2](https://tex.z-dn.net/?f=0%2B2%3D2%5C%5C1%2B1%3D2)
Now adding the rest,
to get ![4](https://tex.z-dn.net/?f=4)
should not give anything to carry as that will make A in decimal to satisfy the addition.
Therefore,
![B+B \ has \ to \ be 1+1=2,+ 1 \ carry=3](https://tex.z-dn.net/?f=B%2BB%20%5C%20has%20%5C%20to%20%5C%20be%201%2B1%3D2%2C%2B%201%20%5C%20carry%3D3)
Thus ![B= 1](https://tex.z-dn.net/?f=B%3D%201)
And finally,
![A+A=12\\A=6](https://tex.z-dn.net/?f=A%2BA%3D12%5C%5CA%3D6)
Thus ![A=6, B=1 \ and \ C=7](https://tex.z-dn.net/?f=A%3D6%2C%20B%3D1%20%5C%20and%20%5C%20C%3D7)
Now simplifying
![A+B+C\\=6+1+7\\=14](https://tex.z-dn.net/?f=A%2BB%2BC%5C%5C%3D6%2B1%2B7%5C%5C%3D14)
Thus
is the answer.