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Vedmedyk [2.9K]
3 years ago
12

If f(x) = 3x – 2 and g(x) = 2x + 1, find (f + g)(x). please help :C

Mathematics
2 answers:
Ostrovityanka [42]3 years ago
7 0

Answer:

5x-2

Step-by-step explanation:

If f(x) = 3x – 2 and g(x) = 2x + 1

we need to find (f + g)(x)

(f + g)(x)= f(x) + g(x)

Replace f(x) and g(x) in the given equation

(f + g)(x)= f(x) + g(x)=3x-3+2x+1

Now we combine like terms

(f + g)(x)= f(x) + g(x)=3x-3+2x+1=5x-2

(f + g)(x)=5x-2

Luba_88 [7]3 years ago
3 0
(f+g)(x) = f(x) + g(x)

(f+g)(x) = 3x-2 + 2x+1

(f+g)(x) = (3x+2x) + (-2+1)

(f+g)(x) = 5x - 1
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A point $(x, y)$ with integer coordinates is randomly selected such that $0 \le x \le 8$ and $0 \le y \le 4$. what is the probab
ahrayia [7]

Answer:

\frac{1}{3}

Step-by-step explanation:

A point (x, y) with integer coordinates is randomly selected such that 0 \le x \le 8 \:and\: $0 \le y \le 4$.

The possible pairs of (x,y) are:

(0,0),(0,1),(0,2),(0,3),(0,4)

(1,0),(1,1),(1,2),(1,3),(1,4)

(2,0),(2,1),(2,2),(2,3),(2,4)

(3,0),(3,1),(3,2),(3,3),(3,4)

(4,0),(4,1),(4,2),(4,3),(4,4)

(5,0),(5,1),(5,2),(5,3),(5,4)

(6,0),(6,1),(6,2),(6,3),(6,4)

(7,0),(7,1),(7,2),(7,3),(7,4)

(8,0),(8,1),(8,2),(8,3),(8,4)

The Total Possible Outcomes n(S)= 45

The pair (x, y) that satisfies the given condition (say event A: x + y \le 4) are:

(0,0),(0,1),(0,2),(0,3),(0,4)\\(1,0),(1,1),(1,2),(1,3)\\(2,0),(2,1),(2,2)\\(3,0),(3,1)\\(4,0)

n(A)=15

Therefore:

P(A)=\frac{n(A)}{n(S)} =\frac{15}{45} =\frac{1}{3}

5 0
3 years ago
Please help me Simplify: 6! − 3!
djverab [1.8K]

Answer: Option B 3!((6×5×4)-1)

Step-by-step explanation:

6! - 3!

= (1×2×3×4×5×6) - (1×2×3)

= 720 - 6

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As you told you forgot to put options lemme answer it.

It will be option B

3!((6×5×4)-1)

It will be 6((6×5×4)-1)

= 6(120) -6

= 720 - 6

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please click thanks and mark brainliest if you like :)

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