(3)(-5x+y=-3)
(5)(3x-8y=24)
-15x+3y=-9
15x-40y=120
3y=-9
-40y=120
-37y=111
Divide both sides by -37
y=-3
To solve for x. Choose one equation from the given and plug what you get in Y.
I'll choose, -5x+y=-3
So, -5x+(-3)=-3
-5x=0
Divide both sides by -5
x=0/-5
Hope, this helps.
Answer: A & C
<u>Step-by-step explanation:</u>
HL is Hypotenuse-Leg
A) the hypotenuse from ΔABC ≡ the hypotenuse from ΔFGH
a leg from ΔABC ≡ a leg from ΔFGH
Therefore HL Congruency Theorem can be used to prove ΔABC ≡ ΔFGH
B) a leg from ΔABC ≡ a leg from ΔFGH
the other leg from ΔABC ≡ the other leg from ΔFGH
Therefore LL (not HL) Congruency Theorem can be used.
C) the hypotenuse from ΔABC ≡ the hypotenuse from ΔFGH
at least one leg from ΔABC ≡ at least one leg from ΔFGH
Therefore HL Congruency Theorem can be used to prove ΔABC ≡ ΔFGH
D) an angle from ΔABC ≡ an angle from ΔFGH
the other angle from ΔABC ≡ the other angle from ΔFGH
AA cannot be used for congruence.
Tan80=5.67
2tan70+tan10=5.67
So tan80=2tan70+tan10
Answer:
A
Step-by-step explanation:
I think it's A because it mostly multiplies then adds and subtracts so you get your answer doing this
