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3 years ago

Ugh help plz I don’t get this

Mathematics

1 answer:

STatiana [176]3 years ago

7 0

The answer is athe answer is a, although your mouse was in the way so slightly difficult to read

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Please I need your help on this.

just olya [345]

Answer:

the answer is 7 7/8

Step-by-step explanation:

1. you will need to change the fractions into an improper fraction.

2. you need to then multiply the numerator and denominator to get a 63/8

3. change 63/8 into a mixed fraction leaving you with 7 7/8

8 0

3 years ago

An odd number between 301 and 370 has three different digits. If the sum of its digits is five times the hundreds digit, find th

damaskus [11]

For the answer to the question above, <span>
5x3 (the hundreds digit)= 15
so 3+x+y=15. 15-3=12. x+y=12.
No even number + odd number can be = 12, so both digits must be odd.
That leaves us with 3+3+z=15, 3+3+x =15 and 3+5+y= 15. 3+1+9 (highest odd digit)= 13 so that is wrong.
3+3+9= 15, but there is a double digit, so wrong again. 3+5+7=15. 357 is the answer.</span>

5 0

3 years ago

Mike's electronics store sold the following number of cellphones on each of the seven days of a week. DayCell Phones Sold Sunday

bulgar [2K]

Answer:

Step-by-step explanation:

The mean is the sum divided by the number of contributors:

(12 +10 +9 +5 +14 +10 +10)/7 = 70/7 = 10

The mean number of phones sold for the week was 10 phones.

6 0

3 years ago

Which value is the solution for this equation?

boyakko [2]

The anwser is y = 6 or c

3 0

3 years ago

Read 2 more answers

A random sample of 121 automobiles traveling on an interstate showed an average speed of 73 mph. from past information, it is kn

tatiyna

121 is big enough to assume normality and not worry about the t distribution. By the 68-95-99.7 rule a 95% confidence interval includes plus or minus two standard deviations. So 95% of the cars will be in the mph range

$(73 - 2 \cdot 11, 73 + 2 \cdot 11) = (51,95)$

The question is a bit vague, but it seems we're being asked for the 95% confidence interval on the average of 121 cars. The 121 is a hint of course.

The standard deviation of the average is in general the standard deviation of the individual samples divided by the square root of n:

$\sigma = \dfrac{ 11}{\sqrt{121}} = 1$

So repeating our experiment of taking the average 121 cars over and over, we expect 95% of the averages to be in the mph range

$(73 - 2 \cdot 1, 73 + 2 \cdot 1) = (71,75)$

That's probably the answer they're looking for.

4 0

3 years ago