The Following steps are used to rewrite the polynomial expression 3(x+4y) + 5(2x-y)

1 answer:

6 0

Let's solve this problem step by step.

1. First of all we have this equation:

$3(x + 4y) + 5(2x - y)$

2. Let's apply distributive property:

$3x+12y + 10x - 5y$

3. Let's order this expression according to the variables:

$3x + 10x + 12y-5y$

4. Let's sum equal terms:

$13x + 7y$

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.The sum of the angles of a polygon is 900⁰ .How many sides does it have

DanielleElmas [232]

Answer:

heptagon

Step-by-step explanation:

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2 years ago

please help! I need to solve kt algebraically and if you can show your work/explain how you got the answer that would help a ton

Tasya [4]

Step-by-step

=> 900=-100x+300

=> -100x+300=900

=> -100x=900–300

=> -100x=600 divide both side by -100

=> x=-6

3 0

2 years ago

Read 2 more answers

Middle School: Math (10 Points)

sasho [114]

1) Our marbles will be blue, red, and green. You need two fractions that can be multiplied together to make 1/6. There are two sets of numbers that can be multiplied to make 6: 1 and 6, and 2 and 3. If you give the marbles a 1/1 chance of being picked, then there's no way that a 1/6 chance can be present So we need to use a 1/3 and a 1/2 chance. 2 isn't a factor of 6, but 3 is. So we need the 1/3 chance to become apparent first. Therefore, 3 of the marbles will need to be one colour, to make a 1/3 chance of picking them out of the 9. So let's say 3 of the marbles are green. So now you have 8 marbles left, and you need a 1/2 chance of picking another colour. 8/2 = 4, so 4 of the marbles must be another colour, to make a 1/2 chance of picking them. So let's say 4 of the marbles are blue. We know 3 are green and 4 are blue, 3 + 4 is 7, so the last 2 must be red.
The problem could look like this:

A bag contains 4 blue marbles, 2 red marbles, and 3 green marbles. What are the chances she will pick 1 blue and 1 green marble?

You should note that picking the blue first, then the green, will make no difference to the overall probability, it's still 1/6. Don't worry, I checked

2) a - 2% as a probability is 2/100, or 1/50. The chance of two pudding cups, as the two aren't related, both being defective in the same packet are therefore 1/50 * 1/50, or 1/2500.

b - 1,000,000/2500 = 400
400 packages are defective each year

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3 years ago

A triangle with sides 11m , 13m and 18m is a right triangle. A True B False

Julli [10]

$\bold{\huge{\pink{\underline{ Solution}}}}$

$\bold{\underline{ Given :-}}$

A triangle with sides 11m, 13m and 18m

$\bold{\underline{ To \: Find :-}}$

We have to check it whether it is right angled triangle or not?

$\bold{\underline{ Let's \: Begin :-}}$

$\sf{\red{ In \:right \:angled\ : triangle, }}$

According to the Pythagoras theorem, The sum of the squares of perpendicular height and the square of the base of the triangle is equal to the square of hypotenuse that is sum of the squares of two small sides equal to the square of longest side of the triangle.

We imply it in the given triangle ,

$\sf{\red{ ( Perpendicular)² + (Base)² = (Hypotenuse)²}}$