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4 years ago

687582 the value of the 8 in the ten thousands place is how many thousands greater than the value of the 8 in the tens place

1 answer:

8 0

The easiest way that I've done these is to break it up. The 8 in the ten thousands place is equal to 80,000, and the 8 in the tens place is equal to 80. Then, compare. The ten thousands has 3 more 0s in it then the ten, so therefore it would be 1,000 times greater.

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What is the solution to the equation 1 over the square root of 8 = 4(m + 3)?

AnnyKZ [126]

The solution would be ... m = <span>√2 - 48 over 16. Have a good day :)</span>

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3 years ago

Can you help me? Please

Anni [7]

9514 1404 393

Answer:

Step-by-step explanation:

For an even-index radical, ...

$\sqrt[n]{x^n}=|x|\qquad\text{n even}$

This lets us simplify the given expression as follows:

$\sqrt[4]{81x^6y^4}-|y|\sqrt[4]{x^6}-\sqrt[4]{16x^2}=\sqrt[4]{(3xy)^4x^2}-|y|\sqrt[4]{x^4x^2}-\sqrt[4]{2^4x^2}\\\\=3|xy|\sqrt[4]{x^2}-|xy|\sqrt[4]{x^2}-2\sqrt[4]{x^2}=\boxed{2|xy|\sqrt[4]{x^2}-2\sqrt[4]{x^2}}$

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3 years ago

One year Terry had the lowest ERA (earned-run average, mean number of runs yielded per nine innings pitched) of any male pitch

Colt1911 [192]

Answer:

Their respective z-scores are:

Thomas : -2.15279

Karla : -1.40221

Which player had the better year relative to their peers, Terry or Karla ?

Terry had a better year because he had a lower Era and he was a better pitcher.

Step-by-step explanation:

The formula for calculating a z-score is is z = (x-μ)/σ,

where x is the raw score,

μ is the population mean

σ is the population standard deviation.

any male pitcher at his school,

For Thomas:

z = (x-μ)/σ

x = 2.85 μ = 4.893 σ = 0.949.

z = 2.85 - 4.893/0.949

z = -2.15279

For Karla

z = (x-μ)/σ

x = 2.95 μ = 4.348 σ = 0.997.

z = (2.95 - 4.348) /0

z = -1.40221

Their respective z-scores are:

Thomas : -2.15279

Karla : -1.40221

Which player had the better year relative to their peers, Terry or Karla ? (Note: In general, the lower the ERA, the better the pitcher.)

Terry had a better year because he had a lower Era and he was a better pitcher.

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3 years ago

General solutions of sin(x-90)+cos(x+270)=-1<br> {both 90 and 270 are in degrees}

mixer [17]

Answer:

$\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.$

Step-by-step explanation:

Given:

$\sin (x-90^{\circ})+\cos(x+270^{\circ})=-1$

First, note that

$\sin (x-90^{\circ})=-\cos x\\ \\\cos(x+270^{\circ})=\sin x$

So, the equation is

$-\cos x+\sin x= -1$

Multiply this equation by $\frac{\sqrt{2}}{2}:$

$-\dfrac{\sqrt{2}}{2}\cos x+\dfrac{\sqrt{2}}{2}\sin x= -\dfrac{\sqrt{2}}{2}\\ \\\dfrac{\sqrt{2}}{2}\cos x-\dfrac{\sqrt{2}}{2}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos 45^{\circ}\cos x-\sin 45^{\circ}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos (x+45^{\circ})=\dfrac{\sqrt{2}}{2}$

The general solution is

$x+45^{\circ}=\pm \arccos \left(\dfrac{\sqrt{2}}{2}\right)+2\pi k,\ \ k\in Z\\ \\x+\dfrac{\pi }{4}=\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{4}\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.$

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4 years ago

La suma de las edades de A y B es 23 años y el producto es 102 años. Hallar ambas edades

KonstantinChe [14]

A+B=23 (17+6= 23)
A*B=102 (17*6= 102)

Las edades serían 17 y 6 años

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3 years ago