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andreev551 [17]
3 years ago
7

Find the area of the figure:

Mathematics
2 answers:
VikaD [51]3 years ago
5 0

Answer:

36 in²

Step-by-step explanation:

First, you find the area of the big rectangle.

5 ⋅ 8 = 40

Second, you find the area of the small square.

2 ⋅ 2 = 4

Finally, you subtract the 2 areas.

40 - 4 = 36

astra-53 [7]3 years ago
4 0

Answer:

To find the area of she shaded part we first need to find the total of the area.

L x W

8 x 5 = 40 is the total area

Now we need to find the area of the non - shaded part

Since it is a square all sides are equal the short lines sticking from the sides indicate that

2 x 2 = 4

Now we subtract the total area from the non shaded area.

40 - 4 = 36

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A negative number raised to an odd power is _____ negative.
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The complete question is as follows.

The equation a = \frac{1}{2}(b_1 + b_2 )h can be used to determine the area , <em>a</em>, of a trapezoid with height , h, and base lengths, b_1 and b_2. Which are equivalent equations?

(a) \frac{2a}{h} - b_2 = b_1

(b) \frac{a}{2h} - b_2 = b_1

(c) \frac{2a - b_2}{h} = b_1

(d) \frac{2a}{b_1 + b_2} = h

(e) \frac{a}{2(b_1 + b_2)} = h

Answer: (a) \frac{2a}{h} - b_2 = b_1; (d) \frac{2a}{b_1 + b_2} = h;

Step-by-step explanation: To determine b_1:

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{h} = b_1 + b_2

\frac{2a}{h} - b_2 = b_1

To determine h:

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{(b_1 + b_2)} = h

To determine b_2

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{h} = (b_1 + b_2)

\frac{2a}{h} - b_1 = b_2

Checking the alternatives, you have that \frac{2a}{h} - b_2 = b_1 and \frac{2a}{(b_1 + b_2)} = h, so alternatives <u>A</u> and <u>D</u> are correct.

4 0
3 years ago
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