What is the decimal equivalent o the rational number 6/11

He paid a deposit of £120 and made 30 monthly payments of £12.<br> How much was the total cost?

yaroslaw [1]

Answer:

480

Step-by-step explanation:

30x12= 360

360+120=480

5 0

3 years ago

∆ABC ~∆DEF, ∆ABC has a heights of 20 inches, and ∆DEF has a height of 24 inches. What is the ratio of the area of ∆ABC to the ar

OLEGan [10]

Answer:

The ratio of the area of ∆ABC to the area of ∆DEF is 25/36

Step-by-step explanation:

∆ABC ~∆DEF

∆ABC has a heights of 20 inches, and ∆DEF has a height of 24 inches

The ratio of the height (h1) of ∆ABC to the height (h2) of ∆DEF is:

h1 / h2= (20 inches) / (24 inches)

h1 / h2= 20 / 24

Simplifying the fraction dividing the numerator and the denominator by 4:

h1 / h2= (20/4) / (24/4)

h1 / h2= 5 / 6

The ratio of the area (A1) of ∆ABC to the area (A2) of ∆DEF is:

A1 / A2 = (h1 / h2)^2

A1 / A2 = (5 / 6)^2

A1 / A2 = 5^2 / 6^2

A1 / A2 = 25 / 36

5 0

3 years ago

Right triangle ABC (C is the right angle) find sin A when a = 3 and b =8

iren [92.7K]

C = 8.5

all you have to do is square 3 and 8 and then add them together and square root

8 0

4 years ago

You are studying the water properties of a bog in eastern Wisconsin and wish to estimate its acidity. You de ne a grid that cove

GenaCL600 [577]

Answer:

$4.8-1.453\frac{1.3}{\sqrt{82}}=4.591$

$4.8+1.453\frac{1.3}{\sqrt{82}}=5.009$

So on this case the 85% confidence interval would be given by (4.591;5.009)

And we can conclude that the true mean for the acidity at 85% of confidence is between (4.591;5.009)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=82-1=81$

Since the Confidence is 0.85 or 85%, the value of $\alpha=0.15$ and $\alpha/2 =0.075$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.075,81)".And we see that $t_{\alpha/2}=1.453$