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Leto [7]
3 years ago
5

Determine if the sequence below is arithmetic or geometric and determine the common difference / ratio in simplest form. 4,9,14,

...
Mathematics
2 answers:
scZoUnD [109]3 years ago
7 0

Answer:

It is an arithmetic sequence and the common difference is 5

Step-by-step explanation:

4+5 = 9; 9+5=14 (adding is arithmetic, multiplying is geometric)

monitta3 years ago
6 0
In an Arithmetic Sequence, there is a common number added or subtracted from each term to get the next
In a Geometric Sequence, there is a common number multiplied or divided from each term to get the next

4, 9, 14
(4+5) = 9
(9+5) = 14

So sequence is arithmetic and the common difference is 5
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Can someone help me on this one pls
frozen [14]

Answer:

d=5

Step-by-step explanation:

6x = 5

d = 6x

if 6x = 5 then d would also equal 5

3 0
3 years ago
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Solve the formula for the variable h f=12gh
Contact [7]
To solve for variable h flip the equation. You get: 12gh=f. After, divide both sides by 12 to get your answer: h=f/12g
8 0
3 years ago
See image help me as fast as possible, please
Arada [10]

Answer: 11.4

Step-by-step explanation:

area of rect. = 24

area of circle (half circle+half circle = full circle) = pi*r^2 = pi*(2*2) = pi*4 = about 12.57

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3 years ago
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Papessa [141]
-19w-3

Step by Step:
Difference means subtraction so:

-14w-3-5w

-19w-3

If this helps, could you mark me brainliest please?
3 0
3 years ago
A certain population of mice is growing exponentially. After one month there are 48. After 2 months there are "192" mice. Write
REY [17]

Answer:

P(t) = 12e^1.3863k

Step-by-step explanation:

The general exponential equation is represented as;

P(t) = P0e^kt

P(t) is the population of the mice after t years

k is the constant

P0 is the initial population of the mice

t is the time in months

If after one month there are 48 population, then;

P(1) = P0e^k(1)

48 = P0e^k ...... 1

Also if after 2 months there are "192" mice, then;

192 = P0e^2k.... 2

Divide equation 2 by 1;

192/48 = P0e^2k/P0e^k

4 = e^2k-k

4 = e^k

Apply ln to both sides

ln4 = lne^k

k = ln4

k = 1.3863

Substitute e^k into equation 1 to get P0

From 1, 48 = P0e^k

48 = 4P0

P0 = 48/4

P0 = 12

Get the required equation by substituting k = 1.3863 and P0 = 12 into equation 1, we have;

P(t) = 12e^1.3863k

This gives the equation representing the scenario

8 0
3 years ago
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