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Katyanochek1 [597]
3 years ago
15

Upon completion of an experiment a student realizes that the technique used for measuring the length and width of a rectangle ha

s a systematic error of 3.8 cm. (The measured length is always more than the actual length.) If the student found the most probable values of the width and length to be 85.7 cm and 123.5 cm, respectively; what is the systematic error of the area of the board
Mathematics
1 answer:
eduard3 years ago
6 0

Answer:

809.4cm²

Step-by-step explanation:

Given the following :

Systematic error = 3.8cm (The measured length is always more than the actual length.)

Most probable dimension :

Width = 85.7 cm

Length = 123.5 cm

Hence most probable area of Rectangle :

Area = Length × Width

Area = 85.7cm × 123.5cm = 10583.95 cm²

Dimension due to Systematic error :

Length = (85.7cm + 3.8cm) = 89.5cm

Width = (123.5cm + 3.8cm) = 127.3cm

Area = Length × width

Area = ( 89.5cm × 127.3) = 11393.35cm²

Systematic error of the area :

value of area with Systematic error - Probable value of area :

11393.35cm² - 10583.95 cm² = 809.4cm²

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Answer:

a < 16

Step-by-step explanation:

We must get a alone to solve this. So first multiply by 2

3a/2 < 24

*2

3a < 48

Divide by 3

a < 16

8 0
2 years ago
PLEASE HELP ME
Zolol [24]
It is 4/3. the quantity of 4 over 3
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8 0
3 years ago
Identify the terms of the expression. 3r^2+4r+8
Andreas93 [3]

Answer:

The terms

Step-by-step explanation:

The terms in this expression are coefficients, constants, variables, and exponents. 3 and 4 would be the coefficients. 8 would be the constant. r is the variable and 2 is the exponent.

4 0
3 years ago
Read 2 more answers
ALGEBRA 1, SEMESTER 2
SIZIF [17.4K]

So firstly, we have to find f(x) when x = 8 and x = 0. Plug the two numbers into the x variable of the function to solve for their f(x):

f(0)=\frac{2*0+3}{3*0-3}\\ f(0)=\frac{0+3}{0-3}\\ f(0)=\frac{3}{-3}\\ f(0)=-1\\ \\ f(8)=\frac{2*8+3}{3*8-3}\\ f(8)=\frac{16+3}{24-3}\\ f(8)=\frac{19}{21}

Now that we have their y's, we can use the slope, aka average rate of change, formula, which is \frac{y_2-y_1}{x_2-x_1} . Using what we have, we can solve it as such:

\frac{\frac{19}{21}-(-1)}{8-0}=\frac{\frac{40}{21}}{8}=\frac{40}{21*8}=\frac{40}{168}=\frac{5}{21}

In short, the average rate of change from x = 0 to x = 8 is 5/21.

8 0
3 years ago
A machining operation produces bearings with diameters that are normally distributed with mean 3.0005 inches and standard deviat
padilas [110]

Answer:

5%

Step-by-step explanation:

The 68-95-99.7 rule for the Normal distribution is an empirical rule that remind us the percentages of data that falls between the mean ± 1, ± 2 and ± 3 standard deviations.

That is to say, if the mean is m and the standard deviation s, roughly speaking 68% of the data falls between  [m-s, m+s], 95% between [m-2s, m+2s] and 99.7% between [m-3s, m+3s].

Since the mean is 3.0005 and the standard deviation is s=0.0010, 2s=0.0020, 95% of the data should fall between [3.0005-0.0020, 3.0005+0.0020] and 5% outside this interval. So <em>around 5% of total production will be scrap</em>.

 

7 0
3 years ago
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