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3 years ago

G(t) = −3t^3 − 4t f (t) = 4t − 4 Find g(t) + f (t)

Mathematics

1 answer:

Anit [1.1K]3 years ago

8 0

Answer:

cDGKSc h

Step-by-step explanation:

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Answer:

$\frac{1}{1 + \cos(x) }$

Step-by-step explanation:

$y = \frac{ \sin(x) }{1 + \cos(x) }$

<u>differentiating numerator wrt x :-</u>

(sinx)' = cos x

<u>differentiating denominator wrt x :- </u>

(1 + cos x)' = (cosx)' = - sinx

Let's say the denominator was "v" and the numerator was "u"

$(\frac{u}{v} )' = \frac{v. \: (u)' - u.(v)' }{ {v}^{2} }$

here,

since u is the numerator u= sinx and u = cos x
v(denominator) = 1 + cos x; v' = - sinx

$= \frac{((1 + \cos \: x) \cos \: x )- (\sin \: x. ( - \sin \: x) ) }{( {1 + \cos(x)) }^{2} }$

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since cos²x + sin²x = 1

$= \frac{ \cos \: x + 1}{(1 + \cos \: x) {}^{2} }$

diving numerator and denominator by 1 + cos x

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G(t) = −3t^3 − 4t f (t) = 4t − 4 Find g(t) + f (t)​

G(t) = −3t^3 − 4t f (t) = 4t − 4 Find g(t) + f (t)