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Arte-miy333 [17]
3 years ago
11

What is the solution to the system of equations? One-fourth x minus one-half y = 8 One-half x + three-fourths y = negative 5 (–8

, –12) (–8, 12) (8, 12) (8, –12)
Mathematics
2 answers:
vesna_86 [32]3 years ago
8 0

Answer:

its (8, -12)

Step-by-step explanation:

I did the test but if you need to show your work then im sorry lol i did it in my head

kiruha [24]3 years ago
3 0

Answer:

Step-by-step explanation:

x/4-y/2=8, x-2y=32, x=32+2y

x/2+3y/4=-5, 2x+3y=-20, x=(-20-3y)/2

32+2y=(-20-3y)/2

64+4y=-20-3y

7y=-84

y=-12, since x=32+2y

x=32+2(-12), x=32-24=8

So the solution is the point (8, -12)

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Find the values of f(x) = 8x²-1 for the domain values {-2,5} (input answers from least to greatest}
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Give the equation of the circle centered at the origin and passing through the point (0, -6).
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Step-by-step explanation:

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8 0
3 years ago
Ill give you Brainlyest! I need help ASAP work shown, please!!<br> problems 8-15
8_murik_8 [283]

Using the segment addition theorem, the solutions are:

5. x = 17

6. x = 7

7. x = 14

BC = 27

CD = 61

BD = 88

8. AB = 26

9. LJ = 46

10. x = 3

11. FG = 15

12. QS = 34

13. BC = 26

14. EG = 19

15. QS = 68

<h3>How to Apply the Segment Addition Theorem?</h3>

The segment addition theorem would be used to solve the problems as shown below:

5. UW = UV + VW [segment addition theorem]

Substitute

6x - 35 = 19 + 4x - 20

6x - 4x = 35 + 19 - 20

2x = 34

x = 17

6. HJ = HI + IJ [segment addition theorem]

Substitute

7x - 27 = 3x - 5 + x - 1

7x - 3x - x = 27 - 5 - 1

3x = 21

x = 7

7. BD = BC + CD [segment addition theorem]

Substitute

7x - 10 = 4x - 29 + 5x - 9

7x - 4x - 5x = 10 - 29 - 9

-2x = -28

x = 14

BC = 4x - 29 = 4(14) - 29 = 27

CD = 5x - 9 = 5(14) - 9 = 61

BD = 7x - 10 = 7(14) - 10 = 88

8. BC = BD

Substitute

2x + 1 = 5x - 26

2x - 5x = -1 - 26

-3x = -27

x = 9

AB = 43 - BC

AB = 43 - 2x + 1 = 43 - 2(9) + 1 = 26

9. 7x - 10 = 9x - 11 - (x + 3)

7x - 10 = 9x - 11 - x - 3

7x - 9x + x = 10 - 11 - 3

-x = -4

x = 4

LJ = 28 + 7x - 10 = 28 + 7(4) - 10

LJ = 46

10. 8x + 11 = 12x - 1

8x - 12x = -11 - 1

-4x = -12

x = 3

11. 11x - 7 = 3x + 9

11x - 3x = 7 + 9

8x = 16

x = 2

FG = 11x - 7 = 11(2) - 7

FG = 15

12. 5x - 3 = 21 - x

5x + x = 21 + 3

6x = 24

x = 4

QS = 2(5x - 3) = 10x - 6 = 10(4) - 6

QS = 34

13. 8x - 20 = 2(3x - 1)

8x - 20 = 6x - 2

8x - 6x = 20 - 2

2x = 18

x = 9

BC = AB = 3x - 1 = 3(9) - 1

BC = 26

14. 5x - 1 = 7x - 13

5x - 7x = 1 - 13

-2x = -12

x = 6

EG = 6x - 4 - 13 = 6(6) - 4 - 13

EG = 19

15. RT - ST = RS

Substitute

8x - 43 - (4x - 1) = 2x - 4

8x - 43 - 4x + 1 = 2x - 4

4x - 42 = 2x - 4

4x - 2x = 42 - 4

2x = 38

x = 19

QS = 2(RS)

QS = 2(2x - 4) = 4x - 8 = 4(19) - 8

QS = 68

Learn more about the segment addition theorem on:

brainly.com/question/28263183

#SPJ1

8 0
2 years ago
(HELP PLEASEE) The area of a rectangular swimming pool is 2x^2+13x-7. Find the dimensions of the swimming pool.
bearhunter [10]

Answer:

length =

2x - 1

width =

x + 7

Step-by-step explanation:

here we go,

=》

2x {}^{2}  + 13x - 7

=》

2 {x}^{2}  + 14x - x - 7

=》

2x(x + 7) - 1(x + 7)

=》

(2x - 1)(x + 7)

here, we got

the dimensions as :-

(2x - 1) \:  \: and \:  \: (x + 7)

7 0
3 years ago
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