The given expression is
16(30x−24y)−18(32x−16y)<span> = ?
</span>
The first term = 16 ( 30x - 24y ) = 480x - 384y
The second term = -18 ( 32x - 16y) = -576x + 288y
Add the two terms:
( 480x - 384y ) + ( -576x + 288y)
= ( 480x - 576x) + ( -384y + 288y)
= -96x -96y
= -96 ( x + y)
The equivalent expression is [-96x -96y] OR -96(x+y)
Answer:
No, the reference point selected for the properties of a substance does't have any effect on thermodynamic analysis.
Step-by-step explanation:
Consider the provided information.
We need to determine that the reference point selected for the properties of a substance have any effect on thermodynamic analysis.
The answer for this question is No.
The reference point selected for the properties of a substance does't have any effect on thermodynamic analysis.
Because in thermodynamic analysis we are deal with the change in the properties.
If we are doing calculation, the reference state chosen is irrelevant as long as we use values in a single consistent array of tables and charts.
Hence, The reference point selected for the properties of a substance does't have any effect on thermodynamic analysis.
True because log times A and B will also be logA and Log B
Step-by-step explanation:
- On the Y-axis where the 2 is you go 3 to the right and put your point right there above the 3.
- There you have your answer on the graph.
