Let α represent the acute angle between the horizontal and the straight line from the plane to the station. If the 4-mile measure is the straight-line distance from the plane to the station, then
sin(α) = 3/4
and
cos(α) = √(1 - (3/4)²) = (√7)/4
The distance from the station to the plane is increasing at a rate that is the plane's speed multiplied by the cosine of the angle α. Hence the plane–station distance is increasing at the rate of
(440 mph)×(√7)/4 ≈ 291 mph
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1) slope is 6 and y-intercept is ( 0,5) y = mx + b, m = 6, b = 5 y = 6x + 5 2)line passes through the points ( 3,6) and ( 6,3 ) First find the slope: m = (3-6)/(6-3) = -3/3 = -1 y = -x + b Plug in one of the given points (x,y) and find b 6 = -3 + b 9 = b <span> y = -x + 9</span> a horizontal line that passes through the point ( -1,7)Horizontal lines have a constant y-value and formaty = c where c is a constant number. y = 7 y=-3x+3x intercept: set y = 0 and solve for x0 = -3x + 33x = 3x = 1x-intercept: (1, 0) y-intercept: set x = 0 and solve for yy = -3(0) + 3y = 3y-intercept: (0,3) y=0,5x-1Is this two equations? The line y=0 has y-intercept at (0,0)The x-intercept is the entire x-axis y=5x-1x -intercept: Set y = 0 and solve for x y-intercept: Set x = 0 and solve for y
Answer:
12r2+r−7
Step-by-step explanation:
hope it helped
-6-y / 3-7 = -2/3
-6-y / -4 = -2/3
Multiply through by -12:-
3(-6-y) = 8
-18 - 3y = 8
3y = - 26
y = -8 2/3
