The z value for a 97. 8% confidence interval estimation is.

Mathematics

1 answer:

VARVARA [1.3K]2 years ago

4 0

Using the z-distribution, it is found that the z-value is of z = -2.29.

<h3>How to find the critical value of Z?</h3>

For a confidence level of $\alpha$ , it is Z with a p-value of $\frac{1 + \alpha}{2}$ .

We have a 97.8% confidence level, hence $\alpha = 0.978$ , z is the value of Z that has a p-value of $\frac{1+0.978}{2} = 0.989$ , so the critical value is z = -2.29.

More can be learned about the z-distribution at brainly.com/question/25890103

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