The standard form for the equation of a circle is :
<span><span> (x−h)^2</span>+<span>(y−k)^2</span>=r2</span><span> ----------- EQ(1)
</span> where handk are the x and y coordinates of the center of the circle and r<span> is the radius.
</span> The center of the circle is the midpoint of the diameter.
So the midpoint of the diameter with endpoints at (2,-5)and(8,-9) is :
((2+(8))/2,(-5+(-9))/2)=(5,-7)
So the point (5,-7) is the center of the circle.
Now, use the distance formula to find the radius of the circle:
r^2=(2−(5))^2+(-5−(-7))^2=9+4=13
⇒r=√13
Subtituting h=5, k=-7 and r=√13 into EQ(1) gives :
(x-5)^2+(y+7)^2=13
It’s 40:15 because 8*5=40 and 3*5=15
Answer:
{-2, 2, 4, 5}
Step-by-step explanation:
The domain is the set of x values.
Answer:
slope is undefined
Step-by-step explanation:
Calculate the slope m using the slope formula
m = 
with (x₁, y₁ ) = A(4, 6) and (x₂, y₂ ) = B(4, 3)
m = 
= 
Division by zero is undefined thus the slope of CD is undefined
