If the third term of the aritmetic sequence is 126 and sixty fourth term is 3725 then the first term is 8.
Given the third term of the aritmetic sequence is 126 and sixty fourth term is 3725.
We are required to find the first term of the arithmetic sequence.
Arithmetic sequence is a series in which all the terms have equal difference.
Nth term of an AP=a+(n-1)d
=a+(3-1)d
126=a+2d--------1
=a+(64-1)d
3725=a+63d------2
Subtract second equation from first equation.
a+2d-a-63d=126-3725
-61d=-3599
d=59
Put the value of d in 1 to get the value of a.
a+2d=126
a+2*59=126
a+118=126
a=126-118
a=8
=a+(1-1)d
=8+0*59
=8
Hence if the third term of the arithmetic sequence is 126 and sixty fourth term is 3725 then the first term is 8.
Learn more about arithmetic progression at brainly.com/question/6561461
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Answer:
92.8%
Step-by-step explanation:
you would just subtract 7.2 from 100
9514 1404 393
Answer:
f(x) = x^6 -10x^5 +89x^4
Step-by-step explanation:
For a given zero p with multiplicity n, one of the factors of the polynomial will be (x -p)^n. If the polynomial has real coefficients, then the complex zeros come in conjugate pairs.
The factored form of your polynomial is ...
f(x) = (x -(5 -8i))(x -(5 +8i))(x -0)^4
f(x) = ((x -5)^2 -(8i)^2)(x^4) = (x^2 -10x +89)(x^4)
f(x) = x^6 -10x^5 +89x^4
Answer:
It'll take 6.97 minutes to have only 1 package remaining.
Step-by-step explanation:
This problem can be interpreted as a compounded interest problem, where the initial amount is 172 packages the interest is 52% and the final amount is 1 package. The formula for compounded interest is:
M = C*(1 - r)^(t)
Where M is the final amount, C is the initial amount, r is the interest rate and t is time elapsed. So we have:
1 = 172*(1 - 0.52)^(t)
1 = 172*(0.48)^t
1/172 = 0.48^t
0.48^t = 0.006
log(0.48^t) = log(0.006)
t*log(0.48) = log(0.006)
-0.734*t = -5.116
t = 6.97
It'll take 6.97 minutes to have only 1 package remaining.