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3 years ago

Can someone help solve this

Mathematics

1 answer:

kap26 [50]3 years ago

3 0

Answer:

336 cubic cm

Step-by-step explanation:

Volume of cone + (Volume of Sphere/2)

V (cone) = (π $r^{2}$ h)/3

= π $4^{2}$ (12) ÷ 3

= 64π ≈ 201 cm

V (sphere) = 4/3π $r^{3}$ /2

= [4/3π(4^3)] ÷ 2

= (256π/3) ÷ 2

≈ 43π ≈ 135

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Suppose that computer literacy among people ages 40 and older is being studied and that the accompanying tables describes the pr

Kazeer [188]

Answer:

Step-by-step explanation:

The complete question is given thus:

Suppose that computer literacy among people ages 40 and older is being studied and that the accompanying tables describes the probability distribution for four randomly selected people, where x is the number that are computer literate. Is it unusual to find four computer literates among four randomly selected people?

x P(x)

0 0.16

1 0.25

2 0.36

3 0.15

4 0.08

ANSWER:

The odds that this will occur according to the chart are 0.08, or 8%, so although this is unlikely, it's not terribly unusual.

⇒ NO

So from the following we can say it is not unusual to find four (4) computer literates among four randomly selected people.

ok, so P(1) + P(2) + P(3) + P(4) + P(0) = 0.16+0.25+0.36+0.15+0.08 = 1

Whereas the chance of finding four (4) out of four (4) computer iteration is low when compared to other factors.

cheers i hope this helped !!

3 0

4 years ago

Use the principle of inclusion and exclusion to find the number of positive integers less than 1,000,000 that are not divisable

wel

This is a simple problem based on combinatorics which can be easily tackled by using inclusion-exclusion principle.
We are asked to find number of positive integers less than 1,000,000 that are not divisible by 6 or 4.
let n be the number of positive integers.
∴ 1≤n≤999,999
Let c₁ be the set of numbers divisible by 6 and c₂ be the set of numbers divisible by 4.
Let N(c₁) be the number of elements in set c₁ and N(c₂) be the number of elements in set c₂.

∴N(c₁) = $\frac{999,999}{6} = 166666$
N(c₂) = $\frac{999,999}{4} = 250000$
∴N(c₁c₂) = $\frac{999,999}{24} = 41667$
∴ Number of positive integers that are not divisible by 4 or 6,

N(c₁`c₂`) = 999,999 - (166666+250000) + 41667 = 625000
Therefore, 625000 integers are not divisible by 6 or 4

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4 years ago

How do I find the properties of a parabola

Elanso [62]

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4 years ago

orlando and daisy ordered a pizza for lunch. orlando ate 1/2 of the pizza, and daisy ate 3/8 of the pizza. how much of the pizza

attashe74 [19]

Answer=7/8

1/2+3/8=

to solve this problem, we need the denominators of the fractions to match. lets convert 1/2 to ?/8

1/2=4/8

4/8+3/8=7/8

They ate 7/8 of the pizza together

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3 years ago

-1/2+4×^3+3×+x^4-x^5

Misha Larkins [42]

The answer is going to be 29444

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3 years ago