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3 years ago

50 POINTS ANSWER QUICK

Mathematics

2 answers:

bogdanovich [222]3 years ago

4 0

Answer:

True

Step-by-step explanation:

If each stick figure represents 50 people, 1/2 a stick figure represents 25 people.

Good habits has 4 stick figures 4*50 =200

Making a budget has 3.5 stick figure 3.5 * 50 = 175

The difference is 200-175=25

This is true

3241004551 [841]3 years ago

3 0

Answer:

"Making a Budget" has half a person, which represents half of 50, which is 25. "Good Spending Habits" have a whole extra half which would be 25 more, because "Making a Budget" has 175, and "Good Spending Habits" has 200. if you subtract that, you get 25 more people at "Good Spending Habits", then "Making a Budget", therefore, its true.

Also i already had this written up but i copied it so i can see you comment. hope this helps!

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X/-5=-20 A -100 or 100 B -4 or 4 C 100 D no solution

alexgriva [62]

Move the negative sign to the left

-x/5 = -20

Multiply both sides by 5

-x = -20 × 5

Simplify 20 × 5 to 100

-x = -100

Multiply both sides by -1

x = 100

C. 100

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3 years ago

Read 2 more answers

Use the given endpoint R and the midpoint M of segment RS to find the coordinates of the other endpoint S. (Hint: Use the midpoi

zimovet [89]

Using the given endpoint R (8,0)and the midpoint M (4,-5) , the other endpoint S is (0,-10)

Explanation :

Use the given endpoint R and the midpoint M of segment RS

R (8, 0 ) and M (4, -5 )

Let 'S' be (x2,y2)

Apply the midpoint formula

$(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\$

Endpoint R is (x1,y1) that is (8,0)

Substitute the values and make it equal to M(4,-5)

$(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\\\(\frac{8+x_2}{2},\frac{0+y_2}{2} )=(4,-5)\\\\\frac{8+x_2}{2}=4\\8+x_2=8\\x_2=8-8=0\\x_2=0\\\\\\\frac{0+y_2}{2} =-5\\y_2=-10$

So other endpoint S is (0,-10)

Learn more : brainly.com/question/16829448

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3 years ago

How do you solve systems of equations using matrices? I need help with the steps please

seraphim [82]

The objective function is simply a function that is meant to be maximized. Because this function is multivariable, we know that with the applied constraints, the value that maximizes this function must be on the boundary of the domain described by these constraints. If you view the attached image, the grey section highlighted section is the area on the domain of the function which meets all defined constraints. (It is all of the inequalities plotted over one another). Your job would thus be to determine which value on the boundary maximizes the value of the objective function. In this case, since any contribution from y reduces the value of the objective function, you will want to make this value as low as possible, and make x as high as possible. Within the boundaries of the constraints, this thus maximizes the function at x = 5, y = 0.