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vaieri [72.5K]
2 years ago
9

HELP!!! Need to find the Area (Pic)

Mathematics
1 answer:
PtichkaEL [24]2 years ago
8 0

Answer: 173.82cm^2

Step-by-step explanation:

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One pound of chicken cost $3.00. Jim buys 8 2/3 pounds of chicken. How much does Jim pay for the chicken?
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It would cost 26 dollars because 3 multiplied by 8 is 24 plus 2/3 of 3 is 26 and that is the result of 2/3 of 3 being 2 dollars
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Suppose that y varies inversely as x and that y=8 when x=3. Calculate the value of y when x= 10.
Svetach [21]

\bf \qquad \qquad \textit{inverse proportional variation} \\\\ \textit{\underline{y} varies inversely with \underline{x}} ~\hspace{6em} \stackrel{\textit{constant of variation}}{y=\cfrac{\stackrel{\downarrow }{k}}{x}~\hfill } \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \textit{we know that } \begin{cases} y = 8\\ x = 3 \end{cases}\implies 8=\cfrac{k}{3}\implies 24=k~\hfill \boxed{y = \cfrac{24}{x}} \\\\\\ \textit{when x = 10, what is \underline{y}?}\qquad \qquad y = \cfrac{24}{10}\implies y = \cfrac{12}{5}

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3 years ago
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7 0
2 years ago
Read 2 more answers
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3 years ago
Professor Halen teaches a College Mathematics class. The scores on the midterm exam are normally distributed with a mean of 72.3
lbvjy [14]

Answer:

14.63% probability that a student scores between 82 and 90

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 72.3, \sigma = 8.9

What is the probability that a student scores between 82 and 90?

This is the pvalue of Z when X = 90 subtracted by the pvalue of Z when X = 82. So

X = 90

Z = \frac{X - \mu}{\sigma}

Z = \frac{90 - 73.9}{8.9}

Z = 1.81

Z = 1.81 has a pvalue of 0.9649

X = 82

Z = \frac{X - \mu}{\sigma}

Z = \frac{82 - 73.9}{8.9}

Z = 0.91

Z = 0.91 has a pvalue of 0.8186

0.9649 - 0.8186 = 0.1463

14.63% probability that a student scores between 82 and 90

3 0
3 years ago
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